问题

我尝试在特定文件夹的所有子目录中查找所有的project.json文件：

import glob from 'glob';

glob.sync('apps/**/project.json', {
    ignore: ['apps/**-e2e/project.json']
})

这会给我一个类似以下的结果：

[
    'apps/something/project-e2e/project.json',
    'apps/something/project/project.json'
]

我想要忽略所有以 e2e 结尾的文件夹。这是否可能？我的尝试使用 ignore 部分不起作用。

英文:

I try to find all project.json files in all subdirectories of a specific folder:

import glob from &#39;glob&#39;

glob.sync(&#39;apps/**/project.json&#39;, {
    ignore: [&#39;apps/**-e2e/project.json&#39;]
})

This gives me a result like:

[
    &#39;apps/something/project-e2e/project.json&#39;,
    &#39;apps/something/project/project.json&#39;
]

I would like to ignore all folders, which ends with e2e. Is this possible. My attempt using the ignore part doesn't work

答案1

得分: 1

在代码中添加额外的 /*，也许 ** 不允许部分目录名称。

import glob from 'glob';

glob.sync('apps/**/project.json', {
    ignore: ['apps/**/*-e2e/project.json']
})

英文:

Add an extra /*, perhaps the ** doesn't allow for partial directory names

import glob from &#39;glob&#39;

glob.sync(&#39;apps/**/project.json&#39;, {
    ignore: [&#39;apps/**/*-e2e/project.json&#39;]
})

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