英文:
Replace just last matching result with regex
问题
如何只用正则表达式替换最后一个匹配结果？
示例：
path = /:demo/:demo1/:demo2path.replace(new RegExp('/:[^/]+'), '/(?<pathinfo>[^/]+)')
如何始终只替换最后一个？
输出应该是：
/:demo/:demo1/(?<pathinfo>[^/]+)
英文:
How can I replace just last matching result with regex?
Example:
path = /:demo/:demo1/:demo2path.replace(new RegExp('/:[^/]+'), '/(?<pathinfo>[^/]+)')
How can I always replace just last one?
Output should be:
/:demo/:demo1/(?<pathinfo>[^/]+)
答案1
得分: 1
function replaceLastMatch(path, regex, replacement) {const matches = path.match(regex);if (matches && matches.length > 0) {const lastMatch = matches[matches.length - 1];const lastIndex = path.lastIndexOf(lastMatch);return path.substring(0, lastIndex) + path.substring(lastIndex).replace(lastMatch, replacement);}return path;}const path = '/:demo/:demo1/:demo2';const regex = /\/:[^/]+(?=\/|$)/g;const replacement = '/(?<pathinfo>[^/]+)';const result = replaceLastMatch(path, regex, replacement);console.log(result); // 输出: /:demo/:demo1/(?<pathinfo>[^/]+)
英文:
Please try below solution this should solve your problem:
function replaceLastMatch(path, regex, replacement) {const matches = path.match(regex);if (matches && matches.length > 0) {const lastMatch = matches[matches.length - 1];const lastIndex = path.lastIndexOf(lastMatch);return path.substring(0, lastIndex) + path.substring(lastIndex).replace(lastMatch, replacement);}return path;}const path = '/:demo/:demo1/:demo2';const regex = /\/:[^/]+(?=\/|$)/g;const replacement = '/(?<pathinfo>[^/]+)';const result = replaceLastMatch(path, regex, replacement);console.log(result); // Output: /:demo/:demo1/(?<pathinfo>[^/]+)
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