JavaScript Regex that matches everything starting with a specific pattern until there's not a whitespace or newline

I was searching for a <b>JavaScript</b> 2015/ES5 and up regex that matches everything starting with a pattern until there's not a blank space or newline, but that does not take in the last space or newline

I'm not looking for a single pattern, but it has to be exchangeable for what you made.

Assuming that the starting text it's

protocol://EVERITING protocol://EVERITING2
protocol://%$&/()= 

and the start pattern it's

protocol:\/\/

has to gives back in matches:

"protocol://EVERITIN"
"protocol://EVERITING2"
"protocol://%$&/()="

It's possible to make something like this?

In javascript (2015/ES5 and up), this should yield the result you're looking for:

<!-- begin snippet: js hide: false console: true babel: true -->

<!-- language: lang-js -->

const input = `protocol://EVERITING protocol://EVERITING2
protocol://%$&/()= 
protocol://sdofihsofhia;sjf.ew/asjodfihapc80hem/ test
donotmatch
protocol:/s/alsodontmatch`

const matches = input.matchAll(/protocol:\/\/\S+/g)

for (const match of matches) {
  console.log(`Found ${match[0]} start=${match.index} end=${match.index + match[0].length}`);
}

// alternatively, in more condensed format:

console.log([...input.matchAll(/protocol:\/\/\S+/g)])

<!-- end snippet -->