英文:
Python len() function reporting 'float' error when handling a list
问题
我有一个列表的列表，我如下初始化：
patches = [[]]
然后我通过patches.append(list_of_x)向主列表追加，通过patches[i].append(x)向子列表追加对象。
当我调用len(patches)时，出现错误“'float' object is not callable”。
我通过type(patches)验证Python仍将其视为列表。
子列表patches[i]中的对象本身具有各种不同的属性，但我认为这应该是无关的（对吗？）。
有没有想法会发生什么样的巫术？
英文:
I have a list of lists that I initiate as follows:
patches = [[]]
and then I append to main list by patches.append(list_of_x), and to the sub lists I append objects by patches[i].append(x).
When I call len(patches) I get error "'float' object is not callable".
I did verify by type(patches) that Python still considers this a list.
The objects within the sub-lists patches[i] themselves have variety of different attributes, but I think that should be irrelevant (right?).
Any idea what kind of witchcraft could be happening?
答案1
得分: 1
我认为你可能在你的代码中之前定义了一个名为 len 的变量。而这个变量很可能是一个浮点数，正如错误所说，你不能调用它。
英文:
I think you might have defined a variable called len before that in your code. And this variable is probably a float, which, as the error says, you can't call.
答案2
得分: 0
不要做补丁 = [[]]
这样做补丁 = []
当你添加时，写入
补丁.append([x，y，x])
就像这样
补丁.append([])
看
v = []
v.append([2,2,5,8,2])
v.append([6,6,8,8,7])
打印(len(v))
2
英文:
don't do patches = [[]]
do it patches = []
when you add, write
patches.append([x,y,x])
like this
patches.append([])
see
v = []
v.append([2,2,5,8,2])
v.append([6,6,8,8,7])
print(len(v))
2
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