我正在尝试使用`Selenium`在`python`中从网站上的表格中的可点击弹出窗口中提取信息到`pandas`数据框中，如果弹出窗口包含信息，似乎可以做到这一点。
```python
from selenium import webdriver
from selenium.webdriver.support.wait import WebDriverWait    
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.support.select import Select
import pandas as pd
import time
driver = webdriver.Chrome()
driver.get('https://mspotrace.org.my/Sccs_list')
time.sleep(20)
# 选择最大条目数
elem = driver.find_element_by_css_selector('select[name=dTable_length]')
select = Select(elem)
select.select_by_value('500')
time.sleep(15)
# 获取元素列表
elements = WebDriverWait(driver, 20).until(EC.presence_of_all_elements_located((By.XPATH, "//a[@title='View on Map']")))
# 循环遍历元素弹出窗口并将设施详情提取到DF
pos = 0
df = pd.DataFrame(columns=['facility_name', 'other_details'])
try:
    for element in elements:
        data = []
        element.click()
        time.sleep(3)
        facility_name = driver.find_element_by_xpath('//h4[@class="modal-title"]').text
        other_details = driver.find_element_by_xpath('//div[@class="modal-body"]').text
        data.append(facility_name)
        data.append(other_details)
        df.loc[pos] = data
        WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "button[aria-label='Close'] > span"))).click()  # 关闭弹出窗口
        time.sleep(10)
        pos += 1
except:
    print("没有地理位置信息")
    pass
print(df)

<details>
<summary>英文:</summary>
I&#39;m trying to scrape some information from clickable popups in a table on a website into a `pandas` dataframe using `Selenium` in `python` and it seems to be able to do this if the popups have information. 
    from selenium import webdriver
    from selenium.webdriver.support.wait import WebDriverWait    
    from selenium.webdriver.common.by import By
    from selenium.webdriver.support import expected_conditions as EC
    from selenium.webdriver.support.select import Select
    import pandas as pd
    import time
    
    driver = webdriver.Chrome()
    driver.get(&#39;https://mspotrace.org.my/Sccs_list&#39;)
    time.sleep(20)
    
    # Select maximum number of entries
    elem = driver.find_element_by_css_selector(&#39;select[name=dTable_length]&#39;)
    select = Select(elem)
    select.select_by_value(&#39;500&#39;)
    time.sleep(15)
    
    # Get list of elements
    elements = WebDriverWait(driver, 20).until(EC.presence_of_all_elements_located((By.XPATH, &quot;//a[@title=&#39;View on Map&#39;]&quot;)))
    
    # Loop through element popups and pull details of facilities into DF
    pos = 0
    df = pd.DataFrame(columns=[&#39;facility_name&#39;,&#39;other_details&#39;])
    
    try:
        for element in elements:
            data = []
            element.click()
            time.sleep(3)
            facility_name = driver.find_element_by_xpath(&#39;//h4[@class=&quot;modal-title&quot;]&#39;).text
            other_details = driver.find_element_by_xpath(&#39;//div[@class=&quot;modal-body&quot;]&#39;).text
            data.append(facility_name)
            data.append(other_details)
            df.loc[pos] = data
            WebDriverWait(driver,20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, &quot;button[aria-label=&#39;Close&#39;] &gt; span&quot;))).click() # close popup window
            time.sleep(10)
            pos+=1
    except:
        print(&quot;No geo location information&quot;)
        pass
    print(df)
However, there are cases when a window like below appears and I need to click &#39;OK&#39; on this to resume scraping the other rows on the web page but I can&#39;t seem to be able to find the element to click on to do this.  
[![enter image description here][1]][1]
  [1]: https://i.stack.imgur.com/NdPqk.png
</details>
# 答案1
**得分**: 0
Selenium驱动程序提供了切换到警报上下文并与之交互的方法：
    driver.switch_to().alert()
之后，根据警报类型，您可以执行所需的操作。要模拟单击“确定”：
    driver.switch_to().alert().accept()
更多信息请参阅[此处](https://www.browserstack.com/guide/alerts-and-popups-in-selenium)。
<details>
<summary>英文:</summary>
Selenium driver provides methods to switch to alerts context and working with it:
    driver.switch_to().alert()
After that, you can do whatever you want, depending on alert type. To simulate clicking on “OK”: 
    driver.switch_to().alert().accept()
More info [here](https://www.browserstack.com/guide/alerts-and-popups-in-selenium)
</details>
# 答案2
**得分**: 0
可以尝试使用 Python：
    driver.switch_to.alert.accept()
但是，您的测试场景应该明确并且应该知道弹出窗口出现的位置。如果您不清楚，或者是“真正”随机的话，您可以检查一些在每个测试步骤中运行的钩子。
<details>
<summary>英文:</summary>
can you try for Pythonenter code here:
    driver.switch_to.alert.accept()
But, your test scenario should be clear and should know where this pop up appears. If you don&#39;t know and &quot;really&quot; random, you can check some hooks that running for each test step
</details>