最长的名字在列表中和所有人的平均出生日期

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英文:

Longest Name in the list and Average birth date of all

问题

以下是代码的翻译部分:

import java.util.ArrayList;
import java.util.Scanner;

public class PersonalDetails {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        
        int sum = 0, count = 0;
        double avg = 0;
        String name;
        String[] pcs;
        String txt;
        
        while(true){
            txt = in.nextLine();
            pcs = txt.split(",");
            
            if(txt.equals("")){
                break;
            }
            
            sum += Integer.valueOf(pcs[1]);
            count++;
        }
        
        String lng = "";
        int low = pcs[0].length();
        for(int i=0; i<txt.length(); i++){
            if(low < pcs[i].length()){
                lng = pcs[i];
            }
        }
        
        if(count>0){
            avg = (double) sum/count;
        }
        
        System.out.println("Longest Name: " + lng);
        System.out.println("Average of the birth years: " + avg);
    }
}

注意:代码中可能存在一些错误,例如循环中的一些逻辑错误,可能需要进一步检查和修复。

英文:

My aim is to calculate the birth date of each person in the list we input as shown below and also output the longest name between them.

Desired output:

sauli,1948
tarja,1943
martti,1936
mauno,1923
urho,1900

Longest name: martti
Average of the birth years: 1930.0

My Code is working but it doesn't output the longest name and correct average.

import java.util.ArrayList;
import java.util.Scanner;

public class PersonalDetails {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        
        int sum = 0, count = 0;
        double avg = 0;
        String name;
        String[] pcs;
        String txt;
        
        while(true){
            txt = in.nextLine();
            pcs = txt.split(&quot;,&quot;);
            
            if(txt.equals(&quot;&quot;)){
                break;
            }
            
            sum += Integer.valueOf(pcs[1]);
            count++;
        }
        
        String lng = &quot;&quot;;
        int low = pcs[0].length();
        for(int i=0; i&lt;txt.length(); i++){
            if(low &lt; pcs[i].length()){
                lng = pcs[i];
            }
        }
        
        if(count&gt;0){
            avg = (double) sum/count;
        }
        
        System.out.println(&quot;Longest Name: &quot; + lng);
        System.out.println(&quot;Average of the birth years: &quot; + avg);
    }
}
`

答案1

得分: 1

name = names.get(0);
for (int i = 1; i < names.size(); i++) {
if (name.length() < names.get(i).length()) {
name = names.get(i);
}
}

/* Another way to resolve your issue is by comparing each input directly and saving it to a variable. */

while (true) {
txt = in.nextLine();
pcs = txt.split(",");
if (name.length() < pcs[0].length()) {
name = pcs[0];
}
if (txt.equals("")) {
break;
}
sum += Integer.valueOf(pcs[1]);
count++;
}

英文:

/* Because you don't save your names to an array and try to get the last input from the scanner which is only empty! to make your program work, you need to initialize an array and save your names to it, after that try to find which name is the longest */

name = names.get(0);
      for(int i=1; i&lt;names.size(); i++){
       if ( name.length()&lt; names.get(i).length()) {
    name = names.get(i);
     }
            
     }

/* Another way to resolve your issue is by comparing each input directly and saving it to a variable. */

 while(true){
 txt = in.nextLine();
 pcs = txt.split(&quot;,&quot;);
    if(name.length()&lt; pcs[0].length()) {
 name=pcs[0];
}
 if(txt.equals(&quot;&quot;)){
 break;
}
 sum += Integer.valueOf(pcs[1]);
count++;
 }

huangapple
  • 本文由 发表于 2023年2月14日 21:21:14
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