英文:
How to exit Python's tcp accept function?
问题
这个程序无法退出，因为accept函数会阻塞。
如果希望程序在超时后即使accept函数仍在运行时也能退出，可以进行以下操作：
import socketimport timeHOST = "127.0.0.1" # 标准回环接口地址（本地主机）PORT = 65432 # 要监听的端口（非特权端口 > 1023）def connect():with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:s.bind((HOST, PORT))print("监听中")s.listen()s.settimeout(5) # 设置超时时间为5秒print("等待连接")try:conn, addr = s.accept()except socket.timeout:print("超时，退出程序")returnprint(f"已连接 {addr}")with conn:while True:data = conn.recv(1024)if not data:breakconn.sendall(data)def main():connect()if __name__ == "__main__":main()
上述代码使用settimeout函数来设置accept函数的超时时间，如果在5秒内没有连接到达，程序会超时退出。
英文:
This program cannot exit because the accept function blocks.
What can be done so that the program exits after a timeout even if the accept function is still running?
# taken from https://realpython.com/python-sockets/#echo-serverimport socketHOST = "127.0.0.1" # Standard loopback interface address (localhost)PORT = 65432 # Port to listen on (non-privileged ports are > 1023)def connect ():with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:s.bind((HOST, PORT))print("listening")s.listen()print("accepting")conn, addr = s.accept() # If these lines arewith conn: # commented, the programprint(f"Connected by {addr}") # exits normally.while True: # This is why I thinkdata = conn.recv(1024) # that the *accept* functionif not data: # is the problembreak #conn.sendall(data) #def main():connect()if __name__ == "__main__":main()
答案1
得分: 1
你可以在服务器套接字上设置超时时间：
>>> import socket>>> s=socket.socket()>>> s.bind(('',5000))>>> s.listen()>>> s.settimeout(5) # 5秒>>> s.accept() # 在这里等待...Traceback (most recent call last): # 5秒后...File "<stdin>", line 1, in <module>File "D:\dev\Python311\Lib\socket.py", line 294, in acceptfd, addr = self._accept()^^^^^^^^^^^^^^TimeoutError: 超时
如果要实现其他行为，可以捕获超时。例如：
def accept(s):''' 等待最多5秒的连接。'''s.settimeout(5)try:results = s.accept()except TimeoutError:return Nones.settimeout(None) # 禁用超时return results
英文:
You can set a timeout on the server socket:
>>> import socket>>> s=socket.socket()>>> s.bind(('',5000))>>> s.listen()>>> s.settimeout(5) # 5 seconds>>> s.accept() # waits here...Traceback (most recent call last): # 5 seconds later...File "<stdin>", line 1, in <module>File "D:\dev\Python311\Lib\socket.py", line 294, in acceptfd, addr = self._accept()^^^^^^^^^^^^^^TimeoutError: timed out
Catch time timeout if you want to implement other behavior. For example:
def accept(s):''' Wait up to 5 seconds for connection.'''s.settimeout(5)try:results = s.accept()except TimeoutError:return Nones.settimeout(None) # disable timeoutreturn results
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