英文:
Check for multiple values with JS include
问题
以下是已翻译的部分：
如果 URL 包含特定字符串，应该返回 true 的功能是存在的：
const doesItContain = () => {
const url = window.location.href;
return url.includes('/items');
};
这个功能在 URL 包含 /items 时返回 true，但当需要检查多个字符串（多个页面）并且如果其中一个存在就返回 true 时会出现问题。例如：
const doesItContain = () => {
const url = window.location.href;
return url.includes('/items', '/users');
};
它仅对列表中的第一个字符串返回 true。是否有一种方法可以同时检查多个字符串？
英文:
There is a function that checks the content of the url with window.location.href. If the URL contains a specific string it should return true:
const doesItContain = () => {
const url = window.location.href;
return url.includes('/items');
};
This works fine, if the url contains /items it returns true. The issue comes when it needs to check for multiple strings (multiple pages) and return true if one of them are present. For example:
const doesItContain = () => {
const url = window.location.href;
return url.includes('/items', '/users');
};
It returns true only for the first string in the list. Is there a way to check for both or more than one string?
答案1
得分: 2
String.prototype.includes 期望一个参数。其他参数将被忽略。
您可以使用 some 来迭代一个字符串数组，并检查是否至少有一个元素满足条件：
const doesItContain = () => {
const url = window.location.href;
return ['/items', '/users'].some(el => url.includes(el));
};
英文:
String.prototype.includes expects one argument. The other arguments are ignored.
You can use some to iterate an array of strings and check if at least one element fullfils the condition:
const doesItContain = () => {
const url = window.location.href;
return ['/items', '/users'].some(el => url.includes(el));
};
答案2
得分: 0
你可以使用正则表达式，使用 | 分隔要检查的每个字符串。
return /\/items|\/users/.test(url);
英文:
You can use a regular expression, separating each of the strings to check with |.
return /\/items|\/users/.test(url);
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