问题

我一直在使用这里的回复来读取 Windows 上文件的元数据。然而，我注意到它会忽略隐藏文件。

如何在这种方法中包括隐藏文件？

答案1

得分: 1

你可以结合Python的os库和Windows的[Shell.Application][2]对象，就像[这里][3]所示的一样，类似这样：

import os
import win32com.client

sh = win32com.client.gencache.EnsureDispatch('Shell.Application', 0)
path = r'c:\mypath\myfolder'
ns = sh.NameSpace(path)

colnum = 0
columns = []
while True:
    colname = ns.GetDetailsOf(None, colnum)
    if not colname:
        break
    columns.append(colname)
    colnum += 1

for name in os.listdir(path): # 列出所有文件
    print(path + '\\' + name)
    item = ns.ParseName(name)
    for colnum in range(len(columns)):
        colval = ns.GetDetailsOf(item, colnum)
        if colval:
            print('\t', columns[colnum], colval)

隐藏文件将显示（H属性表示隐藏）

...
Attributes HA
...

[1]: https://docs.python.org/3/library/os.html
[2]: https://learn.microsoft.com/en-us/windows/win32/shell/shell-application
[3]: https://stackoverflow.com/a/12541871/403671

<details>
<summary>英文:</summary>

You can combine python&#39;s [os library][1] with Windows&#39; [Shell.Application][2] object, as done [here][3], something like this:

    import os
    import win32com.client
    
    sh = win32com.client.gencache.EnsureDispatch(&#39;Shell.Application&#39;, 0)
    path = r&#39;c:\mypath\myfolder&#39;
    ns = sh.NameSpace(path)
    
    colnum = 0
    columns = []
    while True:
        colname=ns.GetDetailsOf(None, colnum)
        if not colname:
            break
        columns.append(colname)
        colnum += 1
    
    for name in os.listdir(path): # list all files
        print(path + &#39;\\&#39; + name)
        item = ns.ParseName(name)
        for colnum in range(len(columns)):
            colval=ns.GetDetailsOf(item, colnum)
            if colval:
                print(&#39;\t&#39;, columns[colnum], colval)

hidden files will display (H attribute is for Hidden)

    ...
    Attributes HA
    ...

  [1]: https://docs.python.org/3/library/os.html
  [2]: https://learn.microsoft.com/en-us/windows/win32/shell/shell-application
  [3]: https://stackoverflow.com/a/12541871/403671

</details>