英文:
Handling a specific runtime error in Go loop
问题
我想在以下循环中捕获panic: runtime error: index out of range错误（在没有返回的函数内部），并将每个panic: runtime error: index out of range的X连接到结果中：
func transform(inputString string, inputLength int) string {
var result = ""
for index := 0; index < inputLength; index++ {
if string(inputString[index]) == " " {
result = result + "%20"
} else {
result = result + string(inputString[index])
}
}
return result
}
例如，对于inputString = Mr Smith和inputLength = 10，result将是Mr%20SmithXX。它有两个X，因为10 - 8 = 2。
我知道我可以在从transform()返回时捕获panic，但我想在循环内部处理它，而不返回函数。
英文:
I'd like to catch panic: runtime error: index out of range in the following loop (inside function without returning) and concat X for each panic: runtime error: index out of range to the result:
func transform(inputString string, inputLength int) string {
var result = ""
for index := 0; index < inputLength; index++ {
if string(inputString[index]) == " " {
result = result + "%20"
} else {
result = result + string(inputString[index])
}
}
return result
}
for example for inputString = Mr Smith and inputLength = 10 the result is Mr%20SmithXX. It has two X because 10 - 8 = 2.
I know I can catch the panic in returning from transform() but I'd like to handle it inside the loop without returning the function.
答案1
得分: 0
> inputString = Mr Smith and inputLength = 10 the result is Mr%20SmithXX. It has two X because 10 - 8 = 2.
package main
import "fmt"
func transform(s string, tLen int) string {
t := make([]byte, 0, 2*tLen)
for _, b := range []byte(s) {
if b == ' ' {
t = append(t, "%20"...)
} else {
t = append(t, b)
}
}
for x := tLen - len(s); x > 0; x-- {
t = append(t, 'X')
}
return string(t)
}
func main() {
s := "Mr Smith"
tLen := 10
fmt.Printf("%q %d\n", s, tLen)
t := transform(s, tLen)
fmt.Printf("%q\n", t)
}
https://go.dev/play/p/wg7MIO8yUzF
"Mr Smith" 10
"Mr%20SmithXX"
英文:
> inputString = Mr Smith and inputLength = 10 the result is Mr%20SmithXX. It has two X because 10 - 8 = 2.
package main
import "fmt"
func transform(s string, tLen int) string {
t := make([]byte, 0, 2*tLen)
for _, b := range []byte(s) {
if b == ' ' {
t = append(t, "%20"...)
} else {
t = append(t, b)
}
}
for x := tLen - len(s); x > 0; x-- {
t = append(t, 'X')
}
return string(t)
}
func main() {
s := "Mr Smith"
tLen := 10
fmt.Printf("%q %d\n", s, tLen)
t := transform(s, tLen)
fmt.Printf("%q\n", t)
}
https://go.dev/play/p/wg7MIO8yUzF
"Mr Smith" 10
"Mr%20SmithXX"
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