英文:
Handling command drift on golang
问题
当从用户端输入数组数据时，输入n = 5后，a[0]自动被赋值为0，并忽略继续输入a[1]。我在其他机器和replit上尝试过，但似乎只在我的电脑上发生。我还尝试卸载和重新安装golang，但没有解决这个问题。
package main
import (
"fmt"
)
func main() {
var a = [100]int{}
var n int
fmt.Print("N = ")
fmt.Scanf("%v", &n)
for i := 0; i < n; i++ {
fmt.Printf("a[%v] = ", i)
fmt.Scanf("%v", &a[i])
}
for i := 0; i < n; i++ {
fmt.Printf("%v ", a[i])
}
fmt.Println()
}
英文:
when entering data for the array from the user side. After entering n = 5 the end a[0] is automatically assigned to 0 and is ignored to continue typing a[1]. I tried on other machines and replit but it seems to only happen on my computer. I also tried uninstalling and reinstalling golang but it didn't fix it
package main
import (
"fmt"
)
func main() {
var a = [100]int{}
var n int
fmt.Print("N = ")
fmt.Scanf("%v", &n)
for i := 0; i < n; i++ {
fmt.Printf("a[%v] = ", i)
fmt.Scanf("%v", &a[i])
}
for i := 0; i < n; i++ {
fmt.Printf("%v ", a[i])
}
fmt.Println()
}
答案1
得分: 1
这将为您解决问题，重要的是在Go语言中进行调试。
var a = make([]int, 100)
var n int = 5
fmt.Print("N = ")
fmt.Scanf("%v \n", &n)
for i := 0; i < n; i++ {
fmt.Printf("a[%v] = ", i)
_, err := fmt.Scanf("%v \n", &a[i])
if err != nil {
fmt.Println("error", err)
}
}
for i := 0; i < n; i++ {
fmt.Printf("%v ", a[i])
}
fmt.Println()
https://pkg.go.dev/fmt#pkg-overview
英文:
This will solve the problem for you, it's important to debug in go language.
var a = make([]int, 100)
var n int = 5
fmt.Print("N = ")
fmt.Scanf("%v \n", &n)
for i := 0; i < n; i++ {
fmt.Printf("a[%v] = ", i)
_, err := fmt.Scanf("%v \n", &a[i])
if err != nil {
fmt.Println("error", err)
}
}
for i := 0; i < n; i++ {
fmt.Printf("%v ", a[i])
}
fmt.Println()
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