golang struct method to take in multiple argument types

My method looks like:

func (t *Worker) updateInfo(n structType1, node structType2)

However, now i need to use this API to process both structType1 and structType3. Which means n could be structType3.

How do i modify the method to achieve this instead of writing another method like below and duplicate the same code?

func (t *Worker) updateInfo(n structType3, node structType2)

EDIT: These structs are all my own custom defined structs

You can use generics in this case.

For instance, let's assume that structType1 and structType2 have a method called Print.

type  structType1 struct {}
func(st1 structType1) Print() {
 fmt.Println("Calling Print function of structType1")
}

type  structType3 struct {}
func(st3 structType3) Print() {
 fmt.Println("Calling Print function of structType2")
}

We can define a interface type declarations as shown below.

type Struct13 interface {
 Print()
 structType1 | structType3 // type union 
}

Then you need to modify Worker struct and updateInfo function with type parameters. (Note: Print funtion in the Struct13 is for demonstration purpose.)

type Worker[T Struct13] struct{}

func (t *Worker[T]) updateInfo(n T, node structType2) {
 n.Print()
}

We can use above implementations as shown below.

    st1 := structType1{}
    st2 := structType2{}
    st3 := structType3{}


    w1 := Worker[structType1]{}
    w1.updateInfo(st1,st2)

    w2 := Worker[structType3]{}
    w2.updateInfo(st3,st2)

you can use empty interface

func (t *Worker) updateInfo(n interface{}, node structType2)

after go 1.18
you can use any

func (t *Worker) updateInfo(n any, node structType2)

and in the function body

switch v := n.(type) {
    case structType1:
        ...
    case structType3:
        ...
    default:
        ...
}