Best way to bind shell output to a struct in Go?

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英文:

Best way to bind shell output to a struct in Go?

问题

我有一些在某些硬件上运行的芯片,并且我想将shell命令的输出绑定到一个结构体上,以便进行报告/日志记录。

Num item1: 2
INDEX LOAD MODEL_LOAD INST MEM  SHARE_MEM P2P_MEM DEVICE         NAMESPACE
1     2    3          4    50    600         700       1     1
1a     2b    3c          4c    5d    6e         7f       2     2
Num item2: 2
INDEX LOAD MODEL_LOAD INST MEM  SHARE_MEM P2P_MEM DEVICE         NAMESPACE
2a     2b    2c          3    0    0         0       1     1
1     0    0          0    0    0         0       2     2
**************************************************

尝试

cat out.txt | grep -i "Num $1" -A 3 | grep -i nvme | tr -s ' ' | cut -d' ' -f1-7

这实际上还不错,我可以传入一个参数,比如decodersencoders,并获取每个芯片的负载指标。然而,我现在很好奇如何将其绑定到Go中的结构体上的最佳方法。

目前,我可以编写一个自定义的反序列化器,类似于:

func main() {
	out, err := exec.Command("/bin/sh", "metrics.sh", "encoders").Output()
	if err != nil {
		fmt.Println(err)
		log.Fatal(err)
	}

	fmt.Println(string(out))
}

但我觉得肯定有更好的方法,比如将输出转换为JSON并绑定到一个结构体之类的。

英文:

I have some chips running on some hardware and I want to bind the output of a shell command to a struct to do reporting/logging on.

Num item1: 2
INDEX LOAD MODEL_LOAD INST MEM  SHARE_MEM P2P_MEM DEVICE         NAMESPACE
1     2    3          4    50    600         700       1     1
1a     2b    3c          4c    5d    6e         7f       2     2
Num item2: 2
INDEX LOAD MODEL_LOAD INST MEM  SHARE_MEM P2P_MEM DEVICE         NAMESPACE
2a     2b    2c          3    0    0         0       1     1
1     0    0          0    0    0         0       2     2
**************************************************

Attempt

cat out.txt | grep -i "Num $1" -A 3 | grep -i nvme | tr -s ' ' | cut -d' ' -f1-7

This actually isn't too bad, I can pass in an arg like decoders or encoders and get the load metrics for each chip. However, I'm curious now the best way to bind this to a struct in Go.

Currently, what I can do is code up a custom deserializer from something like:

func main() {
	out, err := exec.Command("/bin/sh", "metrics.sh", "encoders").Output()
	if err != nil {
		fmt.Println(err)
		log.Fatal(err)
	}

	fmt.Println(string(out))
}

But I feel like there has to be a better way, like outputting as JSON and binding to a struct or something.

答案1

得分: 2

我会将您的输入文件转换为CSV格式,因为它适用于原始的表格数据,而且Go语言的标准库中有一个CSV编码器/解码器:

awk -v OFS=',' '
    $1 == "Num" {
        count = $3
        type = $2

        getline
        if ( !header++ ) {
            $(NF+1) = "ID"
            print
        }
        for ( id = 1; id <= count; id++ ) {
            getline
            $(NF+1) = type id
            print
        }
    }
' file.txt

<sup>**警告:**该代码没有对字段进行CSV转义</sup>

INDEX,LOAD,MODEL_LOAD,INST,MEM,SHARE_MEM,P2P_MEM,DEVICE,NAMESPACE,ID
1,2,3,4,50,600,700,/dev/nvme0,/dev/nvme0n1,decoders:1
1a,2b,3c,4c,5d,6e,7f,/dev/nvme1,/dev/nvme1n1,decoders:2
2a,2b,2c,3,0,0,0,/dev/nvme0,/dev/nvme0n1,encoders:1
1,0,0,0,0,0,0,/dev/nvme1,/dev/nvme1n1,encoders:2
0,0,0,0,0,0,0,/dev/nvme0,/dev/nvme0n1,scalers:1
1,0,0,0,0,0,0,/dev/nvme1,/dev/nvme1n1,scalers:2

**注意:**使用Go编写解析器来处理您的输入格式应该不难。

英文:

I would convert your input file to CSV, because it suits the original tabular data and also because the Go language have a CSV encoder/decoder in its standard library:

awk -v OFS=&#39;,&#39; &#39;
    $1 == &quot;Num&quot; {
        count = $3
        type = $2

        getline
        if ( !header++ ) {
            $(NF+1) = &quot;ID&quot;
            print
        }
        for ( id = 1; id &lt;= count; id++ ) {
            getline
            $(NF+1) = type id
            print
        }
    }
&#39; file.txt

<sup>Warning: the code doesn't CSV-escape the fields</sup>

INDEX,LOAD,MODEL_LOAD,INST,MEM,SHARE_MEM,P2P_MEM,DEVICE,NAMESPACE,ID
1,2,3,4,50,600,700,/dev/nvme0,/dev/nvme0n1,decoders:1
1a,2b,3c,4c,5d,6e,7f,/dev/nvme1,/dev/nvme1n1,decoders:2
2a,2b,2c,3,0,0,0,/dev/nvme0,/dev/nvme0n1,encoders:1
1,0,0,0,0,0,0,/dev/nvme1,/dev/nvme1n1,encoders:2
0,0,0,0,0,0,0,/dev/nvme0,/dev/nvme0n1,scalers:1
1,0,0,0,0,0,0,/dev/nvme1,/dev/nvme1n1,scalers:2

N.B. Writing a parser in Go for your input format shouldn't be that difficult

答案2

得分: 2

如何直接使用Go语言处理你关心的文本呢?在Go语言中,你将比使用shell工具拥有更多的控制权。

下面是一个小型状态机,它会查找以"Num"开头的文本,以指示一个新的项目的开始。下一行是标题,会被跳过,接下来的行会被转换为一个行对象,并添加到该项目中。在项目之间的边界以及输入文本/文件的末尾,最后一个项目会被添加到所有项目的集合中。

package main

import (
	"bufio"
	"fmt"
	"regexp"
	"strings"
)

var txt = `
Num item1: 2
INDEX LOAD MODEL_LOAD INST MEM  SHARE_MEM P2P_MEM DEVICE         NAMESPACE
1     2    3          4    50    600         700       1     1
1a     2b    3c          4c    5d    6e         7f       2     2
Num item2: 2
INDEX LOAD MODEL_LOAD INST MEM  SHARE_MEM P2P_MEM DEVICE         NAMESPACE
2a     2b    2c          3    0    0         0       1     1
1     0    0          0    0    0         0       2     2
Num item3: 1
INDEX LOAD MODEL_LOAD INST MEM  SHARE_MEM P2P_MEM DEVICE         NAMESPACE
i     iib    iic          iii    zero    zero         zero       i     i
**************************************************
`

var columns = regexp.MustCompile(`\s+`)

type Row struct {
	Index,
	Load,
	Model_Load,
	Inst_Mem,
	Share_Mem,
	P2p_Mem,
	Device,
	Namespace string
}

type Item []Row

func main() {
	r := strings.NewReader(txt)
	scanner := bufio.NewScanner(r)

	items := make([]Item, 0)

	var item Item
	for scanner.Scan() {
		line := scanner.Text()
		line = strings.TrimSpace(line)

		if len(line) == 0 ||
			strings.HasPrefix(line, "***") {
			continue
		}

		// find beginning of an "item": if any previous item, save it and
		// reset item to append future rows; skip header line; continue
		if strings.HasPrefix(line, "Num item") {
			if len(item) > 0 {
				items = append(items, item)
				item = make(Item, 0)
			}
			scanner.Scan() // skip header
			continue
		}

		cols := columns.Split(line, -1)
		row := Row{cols[0], cols[1], cols[2], cols[3], cols[4], cols[5], cols[6], cols[7]}
		item = append(item, row)
	}

	// deal with last/trailing item
	if len(item) > 0 {
		items = append(items, item)
	}

	for i, item := range items {
		fmt.Printf("Item %d\n", i+1)
		for _, row := range item {
			fmt.Println(row)
		}
	}
}

运行以上代码会输出以下结果:

Item 1
{1 2 3 4 50 600 700 1}
{1a 2b 3c 4c 5d 6e 7f 2}
Item 2
{2a 2b 2c 3 0 0 0 1}
{1 0 0 0 0 0 0 2}
Item 3
{i iib iic iii zero zero zero i}

我不知道有更好的方法来创建这个结构体,但它是直接的,而且相当清晰。

英文:

How about starting directly with the text you care about in Go? You'll have far more control in Go than you'll ever have with shell utilities.

This is a little state machine that looks for the leading text, "Num", to indicate the beginning of a new Item. The next line is the header, which is skipped, and following lines are converted to a Row, which are added to that Item. At the boundary between items and at the end of the input text/file, the last Item is added to the set of all Items.

package main

import (
	&quot;bufio&quot;
	&quot;fmt&quot;
	&quot;regexp&quot;
	&quot;strings&quot;
)

var txt = `
Num item1: 2
INDEX LOAD MODEL_LOAD INST MEM  SHARE_MEM P2P_MEM DEVICE         NAMESPACE
1     2    3          4    50    600         700       1     1
1a     2b    3c          4c    5d    6e         7f       2     2
Num item2: 2
INDEX LOAD MODEL_LOAD INST MEM  SHARE_MEM P2P_MEM DEVICE         NAMESPACE
2a     2b    2c          3    0    0         0       1     1
1     0    0          0    0    0         0       2     2
Num item3: 1
INDEX LOAD MODEL_LOAD INST MEM  SHARE_MEM P2P_MEM DEVICE         NAMESPACE
i     iib    iic          iii    zero    zero         zero       i     i
**************************************************
`

var columns = regexp.MustCompile(`\s+`)

type Row struct {
	Index,
	Load,
	Model_Load,
	Inst_Mem,
	Share_Mem,
	P2p_Mem,
	Device,
	Namespace string
}

type Item []Row

func main() {
	r := strings.NewReader(txt)
	scanner := bufio.NewScanner(r)

	items := make([]Item, 0)

	var item Item
	for scanner.Scan() {
		line := scanner.Text()
		line = strings.TrimSpace(line)

		if len(line) == 0 ||
			strings.HasPrefix(line, &quot;***&quot;) {
			continue
		}

		// find beginning of an &quot;item&quot;: if any previous item, save it and
		// reset item to append future rows; skip header line; continue
		if strings.HasPrefix(line, &quot;Num item&quot;) {
			if len(item) &gt; 0 {
				items = append(items, item)
				item = make(Item, 0)
			}
			scanner.Scan() // skip header
			continue
		}

		cols := columns.Split(line, -1)
		row := Row{cols[0], cols[1], cols[2], cols[3], cols[4], cols[5], cols[6], cols[7]}
		item = append(item, row)
	}

	// deal with last/trailing item
	if len(item) &gt; 0 {
		items = append(items, item)
	}

	for i, item := range items {
		fmt.Printf(&quot;Item %d\n&quot;, i+1)
		for _, row := range item {
			fmt.Println(row)
		}
	}
}

That prints the following:

Item 1
{1 2 3 4 50 600 700 1}
{1a 2b 3c 4c 5d 6e 7f 2}
Item 2
{2a 2b 2c 3 0 0 0 1}
{1 0 0 0 0 0 0 2}
Item 3
{i iib iic iii zero zero zero i}

I don't know of a better way to create the struct, but it is direct, and fairly clean.

huangapple
  • 本文由 发表于 2022年9月21日 00:40:13
  • 转载请务必保留本文链接:https://go.coder-hub.com/73790001.html
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