How to use URL from user input in Go?

huangapple go评论80阅读模式
英文:

How to use URL from user input in Go?

问题

我几乎完全不了解Go语言,我目前的问题是从用户输入中读取URL并将其存储到一个变量中,以便作为参数传递给http.Get()函数。

以下是代码:

package main

import (
    "bufio"
    "fmt"
    "net/http"
    "os"
    "reflect"
)

func main() {
    reader := bufio.NewReader(os.Stdin)
    fmt.Print("Enter URL: ")
    txt, _ := reader.ReadString('\n')
    fmt.Println(reflect.TypeOf(txt))   // 获取对象类型
    //url := fmt.Sprintf("http://%s",txt)
    url := "http://google.com"
    fmt.Println(reflect.TypeOf(url))   // 获取对象类型
    resp, err := http.Get(url)
    if err != nil {
        fmt.Printf("%s", err)
        os.Exit(1)
    } else {
        fmt.Printf("%s\n", resp.Status)
    }
}

这段代码运行得很好:

d:\Go\bin>get_status
Enter URL: google.com
string
string
200 OK

但是,当我取消注释代码的第16行(同时注释掉第17行):

url := fmt.Sprintf("%s",txt)
//url := "http://google.com"

以便使用用户输入的URL时,我遇到了一个问题:

d:\Go\bin>get_status
Enter URL: google.com
string
string
Get http://google.com: dial tcp: GetAddrInfoW: No such host is known.

我的代码有什么问题?请帮我解决疑惑! How to use URL from user input in Go?

更新
添加import "strings",并使用url := strings.TrimSpace(fmt.Sprintf("http://%s",txt))修复了问题。

ReadString函数会读取输入直到第一个分隔符出现为止,返回包含分隔符在内的数据的字符串。

英文:

I am almost absolutely new to Go language and my current problem is to read URL from user input into a variable to be passed as an argument to http.Get().

The following code

package main

import (
    "bufio"
    "fmt"
    "net/http"
    "os"
    "reflect"
)

func main() {
    reader := bufio.NewReader(os.Stdin)
    fmt.Print("Enter URL: ")
    txt, _ := reader.ReadString('\n')
    fmt.Println(reflect.TypeOf(txt))   // Get object type
    //url := fmt.Sprintf("http://%s",txt)
    url := "http://google.com"
    fmt.Println(reflect.TypeOf(url))   // Get object type
    resp, err := http.Get(url)
    if err != nil {
        fmt.Printf("%s", err)
        os.Exit(1)
    } else {
        fmt.Printf("%s\n", resp.Status)
    }
}

works perfectly:

d:\Go\bin>get_status
Enter URL: google.com
string
string
200 OK

but when I uncomment line 16 of the code (while commenting out line 17)

url := fmt.Sprintf("%s",txt)
//url := "http://google.com"

to use URL from user input, I get a problem:

d:\Go\bin>get_status
Enter URL: google.com
string
string
Get http://google.com
: dial tcp: GetAddrInfoW: No such host is known.

What could be wrong with my code? Please soothe my pain! How to use URL from user input in Go?

Upd:
import "strings" plus url := strings.TrimSpace(fmt.Sprintf("http://%s",txt)) fixed the problem.

> ReadString reads until the first occurrence of delim in the input,
> returning a string containing the data up to and including the
> delimiter.

答案1

得分: 1

好的,看起来ReadString包括分隔符,所以你可以使用strings包中的TrimSpace函数。这对我来说似乎起作用了。

url = strings.TrimSpace(url)
英文:

Alright, so it appears that ReadString includes the delimiter, so you can use TrimSpace from the strings package. This seemed to do the trick for me.

url = strings.TrimSpace(url)

huangapple
  • 本文由 发表于 2016年1月28日 14:12:23
  • 转载请务必保留本文链接:https://go.coder-hub.com/35054042.html
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