英文:
How do you convert array of byte to array of float64
问题
我正在寻找将字节数组（[]byte）转换为浮点数数组（[]float64）的方法，但我没有任何线索来做到这一点。
我从rtlsdr包（https://pkg.go.dev/github.com/jpoirier/gortlsdr）中读取数据，并希望将其传递给Pwelch算法（https://pkg.go.dev/github.com/mjibson/go-dsp/spectral）。
是否可能将大型字节数组转换为float64？
（+另一个问题：您认为是否可能将Pwelch函数转换为使用uint8？）
非常感谢，
pefr
英文:
I am searching to convert an array of byte ([]byte) to array of float64 ([]float64) but I didn't have any clues to do it.
I read data from rtlsdr package (https://pkg.go.dev/github.com/jpoirier/gortlsdr) and would pass it to Pwelch algorithm (https://pkg.go.dev/github.com/mjibson/go-dsp/spectral)
Is it possible to convert large array of byte to float64 ?
(+ another question: did you think that possible to convert Pwelch function to work with uint8 ?)
Thank you so much,
pefr
答案1
得分: 1
byte/uint8有8位，float64有64位。你可以像这样将[8]byte转换为float64：
package main
import (
"encoding/binary"
"fmt"
"math"
)
func main() {
in := 1.0
// 将float64转换为[8]byte
var bytes [8]byte
binary.LittleEndian.PutUint64(bytes[:], math.Float64bits(in))
// 将[8]byte转换为float64
out := math.Float64frombits(binary.LittleEndian.Uint64(bytes[:]))
fmt.Println(out)
}
你可能想选择binary.BigEndian。这符合你的需求吗？或者你想将长度为8n的byte数组转换为长度为n的float64数组吗？请随意发表评论 
英文:
byte/uint8 has 8 bits, float64 has 64. You can convert [8]byte to float64 like this:
package main
import (
"encoding/binary"
"fmt"
"math"
)
main()
{
in := 1.
// Convert float64 to [8]byte
var bytes [8]byte
binary.LittleEndian.PutUint64(bytes[:], math.Float64bits(in))
// Convert [8]byte to float64
out := math.Float64frombits(binary.LittleEndian.Uint64(bytes[:]))
fmt.Println(out)
}
You may want to chose binary.BigEndian instead.
Is that what you are looking for? Or do you want to convert an array of byte with length 8n to an array of float64 with length n? Feel free to comment
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