英文:
How to repeat the function N times per second?
问题
在Go语言中，如何每秒重复执行函数N次？
你可以这样做：
N := 30 //每秒重复30次
for {
//执行某些操作
time.Sleep(time.Second / time.Duration(N))
}
这样做会使得每次重复之间的时间间隔保持一致。
英文:
How to repeat the function N times per second in Go?
I can:
N := 30 //Repeat 30 times per second
for {
//Do something
time.Sleep(time.Second * time.Duration(N))
}
But that just makes the intervals between repetitions
答案1
得分: 5
有两个选项，都不能保证每秒执行 x 次。
选项一：
将 N 设置为 1/30，这样 sleep 将持续 1/30 秒。
N := 30 //每秒重复 30 次
for {
//做一些事情
time.Sleep(time.Duration(1e9 / N)) //time.second 常量不必要（参见 kostya 的评论）
}
选项二：
将 N 设置为 1，即一秒的睡眠时间。
N := 1 //一秒的睡眠时间
for {
for i := 1; i <= 30; i++ {
//做一些事情
}
time.Sleep(time.Second * time.Duration(N))
}
请注意，在选项二中，所有事情都会一次性发生，然后等待一秒钟。第一个选项将在整个秒钟内分散执行某些操作。由于计算机的时间问题，这不会是精确的：sleep 不能保证它会在你期望的时间精确唤醒。
英文:
There are two options, neither will get you a guaranteed x times per second.
- Set N not to
30but1/30. Thus the sleep will be for 1/30th of a second. - Have an internal for-loop that loops 30 times and executes your 'do something', and then on exit you hit the statement that sleeps for a second.
Option One:
N := 30 //Repeat 30 times per second
for {
//Do something
time.Sleep(time.Duration(1e9 / N)) //time.second constant unnecessary (see kostya comments)
}
Option Two:
N := 1 //Sleep duration of one second
for {
for i := 1; i<=30; i++ {
//Do something
}
time.Sleep(time.Second * time.Duration(N))
}
Note that in option two, everything happens all at once, and then you wait a second. The first option will space out the do something across the second. Because of timing in computers this won't be precise: sleep cannot guarantee it will wake up precisely when you expect.
答案2
得分: 5
你可以使用time.Ticker来处理所有的簿记工作。唯一的“问题”是，如果你的操作花费的时间超过预期，你将会丢失一些滴答声（因此每秒运行的次数会少于N）。
func doSomething() {
const N = 30
ticker := time.NewTicker(time.Second / N)
for range ticker.C {
fmt.Println("做任何不超过1/N秒的事情")
}
}
https://play.golang.org/p/Gq-tWMvxIk
英文:
You can use a time.Ticker to handle all the book-keeping for you. The only "issue" is that if your operation takes longer than expected you'll loose ticks (and thus run fewer than N per second).
func doSomething() {
const N = 30
ticker := time.NewTicker(time.Second / N)
for range ticker.C {
fmt.Println("Do anything that takes no longer than 1/Nth of a second")
}
}
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