英文:
Golang Static folder path returns all files
问题
我有一个用于打开静态文件夹的代码：
fs := http.FileServer(http.Dir("./static/"))router.PathPrefix("/static/").Handler(http.StripPrefix("/static/", fs))
但是当我访问/static路径时，它返回了该文件夹中的文件列表，例如：
license.txtlogo.png
但我想返回一个空白页面。
英文:
i have a this code to open static folder
fs := http.FileServer(http.Dir("./static/"))router.PathPrefix("/static/").Handler(http.StripPrefix("/static/", fs))
but when i'm going to /static path it returns a list of files in this folder
eg
license.txtlogo.png
but i want to return a blank page
答案1
得分: 1
你可以在目录./static/中添加一个空白的index.html文件，它将被渲染为空白页面。
类似于这样：
<html><head><title>这里什么都没有</title></head><body><h1>这里什么都没有</h1></body></html>
英文:
You can add blank index.html in directory ./static/, it will be rendered as blank page.
Something like this
<html><head><title>Nothing here</title></head><body><h1>Nothing here</h1></body></html></details># 答案2**得分**: 0vodolaz095的答案是最简单的，但如果你真的必须在Go中完成，你可以包装`FileServer`来捕获请求根目录的特定情况：```gofunc noIndex(fs http.Handler) http.HandlerFunc {return func(w http.ResponseWriter, r *http.Request) {if r.URL.Path == "" || strings.HasSuffix(r.URL.Path, "/") {w.Write("")return}fs.ServeHTTP(w, r)}}
请注意，这不会捕获URL中没有尾部斜杠的子目录的请求；要捕获这种情况，你需要一个更详细的自定义实现，它需要了解文件系统，知道什么是目录，什么是文件。
英文:
vodolaz095's answer is the simplest, but if you really must do it in Go, you could wrap the FileServer to catch the specific case of a request for the root:
func noIndex(fs http.Handler) http.HandlerFunc {return func(w http.ResponseWriter, r *http.Request) {if r.URL.Path == "" || strings.HasSuffix(r.URL.Path, "/") {w.Write("")return}fs.ServeHTTP(w, r)}}
Note that this doesn't catch requests for subdirectories without a trailing slash in the URL; to trap this you'd need a much more detailed custom implementation that was filesystem-aware to know what is a directory and what is a file.
答案3
得分: 0
看起来你正在使用gorilla/mux，但如果你不介意使用标准库的http.ServeMux，你可以在Go代码中这样实现：
func main() {fs := http.FileServer(http.Dir("./static/"))h := http.NewServeMux()blank := http.HandlerFunc(func(_ http.ResponseWriter, _ *http.Request) {})h.Handle("/static/", http.StripPrefix("/static/", fs)) // 匹配"/static"并重定向...h.Handle("/static", blank) // ...除非你显式地创建一个处理程序http.ListenAndServe(":8080", h)}
来自http.ServeMux文档：
...如果已经注册了一个子树，并且收到了一个不带尾部斜杠的子树根的请求，ServeMux会将该请求重定向到子树根（添加尾部斜杠）。可以通过单独为不带尾部斜杠的路径注册来覆盖此行为。例如，注册"/images/"会导致ServeMux将对"/images"的请求重定向到"/images/"，除非"/images"已经单独注册。
英文:
It looks like you are using gorilla/mux - but if you don't mind using the standard library's http.ServeMux you can achieve this in Go code like so:
func main() {fs := http.FileServer(http.Dir("./static/"))h := http.NewServeMux()blank := http.HandlerFunc(func(_ http.ResponseWriter, _ *http.Request) {})h.Handle("/static/", http.StripPrefix("/static/", fs)) // will match "/static" with a redirect ...h.Handle("/static", blank) // ... unless you create a hanlder explicitlyhttp.ListenAndServe(":8080", h)}
from http.ServeMux docs:
> ...if a subtree has been registered and a request is received naming
> the subtree root without its trailing slash, ServeMux redirects that
> request to the subtree root (adding the trailing slash). This behavior
> can be overridden with a separate registration for the path without
> the trailing slash. For example, registering "/images/" causes
> ServeMux to redirect a request for "/images" to "/images/", unless
> "/images" has been registered separately.
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