英文:
Needing help understanding logic in "Head First Java"
问题
我最近开始第一次使用Java进行编程（只是一种爱好），目前我正在使用一本非常好的书《Head First Java》，但我真的很难理解这些练习。
就像这个例子一样：
class Output {void go() {int y = 7;for(int x = 1; x < 8; x++) {y++; // y现在是8吗？if(x > 4) {System.out.println(++y + " "); // 这会使y = 9吗？}if(y > 14) {System.out.println(" x = " + x);break; // break关键字如何影响循环的其余部分？}}}public static void main(String[] args) {Output o = new Output();o.go();}}
有人能否请解释一下这段代码中发生了什么？
英文:
I have recently started programming in Java for the first time (just as a hobby), and at the moment Im working with a book "Head First Java" that is very good, but I'm really struggling with understanding the exercises.
Like this for example:
class Output {void go() {int y = 7;for(int x = 1; x < 8; x++) {y++; // is y now 8?if(x >4) {System.out.println(++y + " "); // does this make y = 9?}if(y > 14) {System.out.println(" x = " + x);break; // how does the break key word affect the rest of the loop?}}}public static void main(String[] args) {Output o = new Output();o.go();}}
Can someone please explain to me what goes on in this code?
答案1
得分: 1
变量y必须为15，因为您在for循环中多次增加了它的值。
++y将其值增加1。i++和++i非常相似，但并不完全相同。两者都会递增数字，但++i会在当前表达式求值之前递增数字，而i++会在表达式求值之后递增数字。
break只是简单地跳出循环。
英文:
Variable y must be 15, because you increased it's value many times with the for loop.
++y increases it's value by 1. i++ and ++i are very similar but not exactly the same. Both increment the number, but ++i increments the number before the current expression is evaluted, whereas i++ increments the number after the expression is evaluated.
break simply exists from the loop.
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