英文:
Fibonacci sequence using array without using recursion technique
问题
这是方法：
public static void fibonacci_array_calc(int[] array) {System.out.println("Fibonacci Series of " + array.length + " numbers:");if (array.length > 0) {System.out.print("0 ");if (array.length > 1) {System.out.print("1 ");int prev = 0;int current = 1;for (int i = 2; i < array.length; i++) {int next = prev + current;System.out.print(next + " ");prev = current;current = next;}}}}
输出是：
Fibonacci Series of 10 numbers:0 1 1 2 3 5 8 13 21 34
这段代码对于生成斐波那契数列使用了一个更简洁的方法，避免了重复的操作。
英文:
I'm trying to generate a code that will display the Fibonacci sequence using an array I did generate a code that has the right solution but I think it's too long since the instructor told us it's gonna be a maximum of 5 lines of code
So here is the method :
public static void fibonacci_array_calc(int[] array) {int result;System.out.println("Fibonacci Series of " + array.length + " numbers: ");if (array.length == 0 || array.length == 1) {for(int i = 0;i < array.length; i++)System.out.print(array[i] + " ");} else {for (int i = 0; i <= 1; i++) {result = array[i] = i;System.out.print(result + " ");if (array[i] >= 1) {for (int j = 2; j < array.length; i++, j++) {result = (array[j] = (array[i] + array[i - 1]));System.out.print(result + " ");}}}}}
the output is
Fibonacci Series of 10 numbers:0 1 1 2 3 5 8 13 21 34
it's not allowed to use the recursion technique is there any way to shorten this code?
答案1
得分: 1
你可以通过使用条件赋值给array[i]来极大简化你的代码。这个赋值可以在不论输入数组长度的情况下使用：
public static void fibonacci_array_calc(int[] array) {System.out.println("Fibonacci 数列（包含 " + array.length + " 个数字）：");for (int i = 0; i < array.length; i++) {array[i] = i <= 1 ? i : array[i-2] + array[i-1];System.out.print(array[i] + " ");}}
英文:
You can greatly simplify your code by using a conditional assignment to array[i]. This assignment can then be used regardless of the length of the input array:
public static void fibonacci_array_calc(int[] array) {System.out.println("Fibonacci Series of " + array.length + " numbers: ");for (int i = 0; i < array.length; i++) {array[i] = i <= 1 ? i : array[i-2] + array[i-1];System.out.print(array[i] + " ");}}
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