DateTimeParse Exception

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英文:

DateTimeParse Exception

问题

我在解析日期时,代码中一直出现异常错误。日期的格式如下:

Wed May 21 00:00:00 EDT 2008

以下是尝试读取它的代码:

DateTimeFormatter formatter = DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss zzz yyyy");
Property property = new Property();
property.setSale_date(LocalDateTime.parse(linesplit[8], formatter));

预期结果:一个 LocalDateTime,值为 2008-05-21T00:00

然而实际结果为:

异常线程 "main" 中出现 java.time.format.DateTimeParseException:
在索引 0 处无法解析文本 'Wed May 21 00:00:00 EDT 2008'

我这样做完全错误吗?

英文:

I am constantly getting an exception error in my code when parsing a date.
The Date looks like this:

Wed May 21 00:00:00 EDT 2008

This is the code for trying to read it:

DateTimeFormatter formatter = DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss zzz yyyy");
Property property = new Property();
property.setSale_date(LocalDateTime.parse(linesplit[8], formatter));

Expected result: A LocalDateTime of 2008-05-21T00:00.

What I got instead:

> Exception in thread "main" java.time.format.DateTimeParseException:
> Text 'Wed May 21 00:00:00 EDT 2008' could not be parsed at index 0

Am I doing this completely wrong?

答案1

得分: 1

恶魔就在细节中。你基本上做得没错,除了:

  • 你需要为格式化程序提供区域设置。
  • 通过解析成 LocalDateTime,你正在丢失信息,可能会得到意外的结果。

所以我建议:

DateTimeFormatter formatter = DateTimeFormatter.ofPattern(
    "EEE MMM dd HH:mm:ss zzz yyyy", Locale.ROOT);

String linesplit8 = "Wed May 21 00:00:00 EDT 2008";
ZonedDateTime zdt = ZonedDateTime.parse(linesplit8, formatter);

System.out.println(zdt);

输出为:

> 2008-05-21T00:00-04:00[America/New_York]

你的字符串是用英语表示的。看起来像是从 Date.toString() 输出的结果(Date 是 Java 8 之前用于表示时间的旧式类)。所以它可能是英语,因为那个 toString 方法总是生成英语输出。因此,如果你的区域设置不是英语区域,解析可能会失败,我认为这就是失败的原因。在这种情况下,使用 Locale.ROOT 代表区域设置中立的英语区域,表示“在这里不应用任何区域设置特定的处理”。

你的字符串包含一个时区缩写,EDT,它是唯一标识时间点的一部分,因此你也会想要获取这部分信息。所以要使用 ZonedDateTime

链接

有一些相关/类似的问题,例如:

英文:

The devil is in the detail. You are basically doing it correctly, except:

  • You need to provide a locale for the formatter.
  • By parsing into a LocalDateTime you are losing information and possibly getting an unexpected result.

So I suggest:

	DateTimeFormatter formatter = DateTimeFormatter.ofPattern(
			"EEE MMM dd HH:mm:ss zzz yyyy", Locale.ROOT);
	
	String linesplit8 = "Wed May 21 00:00:00 EDT 2008";
	ZonedDateTime zdt = ZonedDateTime.parse(linesplit8, formatter);
	
	System.out.println(zdt);

Output is:

> 2008-05-21T00:00-04:00[America/New_York]

Your string is in English. It looks like the output from Date.toString() (Date being the old-fashioned class used for times before Java 8). So it’s probably in English because that toString method always produced English output. So if your locale is not an English-speaking one, parsing is deemed to fail, and I believe this is the reason why it did. In this case it’s appropriate to use Locale.ROOT for the locale neutral English-speaking locale. A way to say “don’t apply any locale specific processing here”.

Your string contains a time zone abbreviation, EDT, which is part of identifying a unique point in time, so you will want to pick up this part of the information too. Therefore use a ZonedDateTime.

There are some related/similar questions, for example:

答案2

得分: 1

  • 避免使用三个字母的时区标识符。以下是来自Java 6文档的摘录:

三个字母的时区标识符

为了与JDK 1.1.x兼容,还支持一些其他的三个字母的时区标识符(例如“PST”,“CTT”,“AST”)。然而,它们的使用已被弃用,因为同样的缩写通常用于多个时区(例如,“CST”可以是美国的“中部标准时间”和“中国标准时间”),而Java平台只能识别其中之一。

DateTimeFormatter formatter = DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss zzz uuuu", Locale.ENGLISH);

ZonedDateTime zdt = ZonedDateTime.parse("Wed May 21 00:00:00 EDT 2008", formatter);
System.out.println(zdt);

输出

2008-05-21T00:00-04:00[America/New_York]

让我们尝试使用这个格式化器来替换EDT为推荐的 America/New_York的相同日期时间字符串:

ZonedDateTime zdt = ZonedDateTime.parse("Wed May 21 00:00:00 America/New_York 2008", formatter);
System.out.println(zdt);

输出仍然相同。

从**教程: 日期时间中了解更多关于现代日期时间API**的信息。

英文:
  • Avoid using the three-letter time zone ID. Given below is an extract from as old as Java 6 documentation:

> Three-letter time zone IDs
>
> For compatibility with JDK 1.1.x, some other three-letter time zone
> IDs (such as "PST", "CTT", "AST") are also supported. However, their
> use is deprecated
because the same abbreviation is often used for
> multiple time zones (for example, "CST" could be U.S. "Central
> Standard Time" and "China Standard Time"), and the Java platform can
> then only recognize one of them.

DateTimeFormatter formatter = DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss zzz uuuu", Locale.ENGLISH);
    
ZonedDateTime zdt = ZonedDateTime.parse("Wed May 21 00:00:00 EDT 2008", formatter);
System.out.println(zdt);

Output:

2008-05-21T00:00-04:00[America/New_York]

Let's try this formatter for the same date-time string replacing EDT with the recommended America/New_York:

ZonedDateTime zdt = ZonedDateTime.parse("Wed May 21 00:00:00 America/New_York 2008", formatter);
System.out.println(zdt);

The output remains same.

Learn more about the the modern date-time API from Trail: Date Time.

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  • 本文由 发表于 2020年5月31日 00:47:05
  • 转载请务必保留本文链接:https://go.coder-hub.com/62105691.html
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