英文:
One expression to ignore special symbols, numbers, and spacing? Java
问题
以下是我已经完成的部分：
userSent = userSent.replaceAll("\\s+", "")
.replaceAll("[^a-zA-Z0-9]", "")
.replaceAll("[0-9]", "");
如果可能的话，我想用一个表达式来简化这个过程，使用Java语言，非常感谢。
英文:
What I have so far is:
userSent = userSent.replaceAll("\\s+", ""); //replaces all spaces with no spacing
userSent = userSent.replaceAll("[^a-zA-Z0-9]", ""); //remove all special characters
userSent = userSent.replaceAll("[0-9]", ""); //remove all numbers from string
I would like to simplify this to one expression if possible using Java, thanks a bunch.
答案1
得分: 1
这三个替换等同于以下内容：
userSent = userSent.replaceAll("[^a-zA-Z]", "");
（被视为“非字母”的字符集包括数字和空格。）
然而，我怀疑这可能不是你实际想要的，因为它会删除所有不在拉丁字母表中的字符，并将它们全部混合成一个单一的“单词”。这真的是你想要的吗？在我看来，这与你问题标题中描述的问题不匹配。
我的建议是，在尝试将它们组合成一个单一的正则表达式之前，确保这三个替换确实实现了你想要的效果（换句话说...在组合之前测试它们的组合效果）。
英文:
Those three replaces are equivalent to this:
userSent = userSent.replaceAll("[^a-zA-Z]", "");
<sup>(The set of characters that are "not a letter" includes numbers and spaces.)</sup>
However, I suspect that this is not what you actually want because it removes every character that is not in the Latin alphabet and mashes them all into a single "word". Is that really what you want? (To my mind, it doesn't match the problem description in your Question's title.)
My advice would be to make sure that the 3 replaces do what you actually want (in other words ... test them in combination) before you try to combine them into a single regex.
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