英文:
Swapping arrays between min and max
问题
我被分配任务制作一个程序，该程序从10个随机数中找到最大和最小的数，并交换它们的位置。
我的代码：
import java.util.Scanner;public class Main {public static void main(String []args) {Scanner obj = new Scanner(System.in);int[] arr = new int[10];System.out.println("输入10个随机数：");for(int i = 0; i < arr.length; i++) {int num = obj.nextInt();arr[i] = num;}int minIndex = findMinIndex(arr, arr.length);int maxIndex = findMaxIndex(arr, arr.length);// 交换最大和最小数的位置int temp = arr[minIndex];arr[minIndex] = arr[maxIndex];arr[maxIndex] = temp;System.out.print("交换后的数组： ");for (int num : arr) {System.out.print(num + " ");}}static int findMaxIndex(int[] numbers, int length) {int maxIndex = 0;for (int i = 1; i < length; i++) {if (numbers[i] > numbers[maxIndex]) {maxIndex = i;}}return maxIndex;}static int findMinIndex(int[] numbers, int length) {int minIndex = 0;for (int i = 1; i < length; i++) {if (numbers[i] < numbers[minIndex]) {minIndex = i;}}return minIndex;}}
我的问题是在输出行上没有换行，例如：
输入：1 2 3 4 5 6 78 9 5 5
输出：78 2 3 4 5 6 1 9 5 5
英文:
I am tasked to make a program that finds the max and min numbers from 10 random numbers and swap their places.
My code:
import java.util.Scanner;public class Main {public static void main(String []args) {Scanner obj = new Scanner(System.in);int[] arr =new int[10];System.out.println("enter 10 random numbers: ");for(int i = 0 ; i < arr.length; i++){int num = obj.nextInt();arr[i] = num;}int min = findMin(arr, arr.length);int max =findMax(arr, arr.length);System.out.println("max number : " + max + " | min number : " + min);}static int findMax(int[] numbers, int lenght) {int max = numbers[0];for (int i = 1; i < lenght; i++) {if (numbers[i] > max) {max = numbers[i];}}System.out.println();return max;}static int findMin(int[] numbers, int lenght) {int min = numbers[0];for (int i = 1; i < lenght; i++) {if (numbers[i] < min) {min = numbers[i];}}return min;}}
My problem is i dont get print in line
example
imput 1 2 3 4 5 6 78 9 5 5
output 78 2 3 4 5 6 1 9 5 5
答案1
得分: 0
public static void main(String[] args) {Scanner scan = new Scanner(System.in);int[] nums = new int[10];System.out.println("请输入10个整数：");for (int i = 0; i < nums.length; i++) {nums[i] = scan.nextInt();}int max = nums[0];int min = nums[0];for (int i = 0; i < nums.length; i++) {if (min > nums[i]) {min = nums[i];} else if (max < nums[i]) {max = nums[i];}}for (int i = 0; i < nums.length; i++) {if (nums[i] == min) {System.out.print(max + ", ");} else if (nums[i] == max) {System.out.print(min + ", ");} else {System.out.print(nums[i] + ", ");}}System.out.println("\n最大值为：" + max);System.out.println("最小值为：" + min);}
英文:
public static void main(String[] args) {Scanner scan = new Scanner(System.in);int [] nums = new int [10];System.out.println("Please enter 10 ints: ");for(int i = 0;i<nums.length;i++){nums[i] = scan.nextInt();}int max = nums[0];int min = nums[0];for(int i = 0;i<nums.length;i++) {if(min>nums[i]) {min = nums[i];}else if(max<i) {max = nums[i];}}for(int i = 0;i<nums.length;i++) {if(nums[i]==min) {System.out.print(max+", ");}else if(nums[i]==max) {System.out.print(min+", ");}else {System.out.print(nums[i]+", ");}}System.out.println("\nmax is: "+max);System.out.println("min is: "+min);}
this should produce the max and min of a given random array of size 10 with out fault.
答案2
得分: 0
好的，如果您将第12行和第13行更改为（以正确查找最小值和最大值）
min = integer[0];max = integer[0];
并在末尾添加一些代码块（以进行交换）：
integer[minIndex] = max;integer[maxIndex] = min;
那么就可以了。然后您只需打印数组。
英文:
Alright so if you change the 12th and 13th lines to (to find min and max correctly)
min = integer[0];max = integer[0];
And add some piece of code at the end like (to swap):
integer[minIndex] = max;integer[maxIndex] = min;
It would be alright. Then you can just print the array.
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论