Two same programs different outputs?

package com.company;

public class test {
    public static void main(String[] args) {
        int x=5, y=4, z;
        int step1 = (++x + ++y);
        int step2 = (y++ % 2);
        z= step1*step2;
        System.out.println(step1 + "*" + step2);
        System.out.println(z);
    }
}

This program prints 11. I tried inlining step1 and step2 expecting to get the same result but it prints 1 instead.

package com.company;

public class test {
    public static void main(String[] args) {
        int x=5, y=4, z;
        z= (++x + ++y) * y++ % 2;
        System.out.println(z);
    }
}

Why is the output different?

I would suggest you take a look at how java does its operator precedence.

To have your same output, just change your code in the second example to

z = (++x + ++y) * (y++ % 2);

Your code has problem. In java it's working like this.

   z= ((++x + ++y) * y++) % 2;

calculation are

z = ((6 + 5) * 5) % 2

z = (55) % 2

z = 1


for your expected answer, you need to write

   z= (++x + ++y) * (y++ % 2);

now (z = 11)