在不同类别的活动中显示不同的列表项。

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英文:

show different list items on different catagories activities

问题

现在我想要在不同类别中列出项目，例如：其中一个类别是医院，其中一个项目必须包含名称、地址和电话号码。我在适配器中创建了这个if语句，如果索引具有一个文本不可见，其他的文本可见，但是它在我这里运行得不好，需要帮助。

以下是您提供的代码：

  1. public class Data {
  2.     private String placeWord;
  3.     private String addressWord;
  4.     private String reason = ONE_TEXT;
  5.     private static final String ONE_TEXT = "ah";
  7.     public Data(String mPlaceWord, String mAddressWord){
  8.         placeWord = mPlaceWord;
  9.         addressWord = mAddressWord;
  10.     }
  11.     public Data(String theReason){
  12.         reason = theReason;
  13.     }
  14.     public String getPlaceWord(){
  15.         return placeWord;
  16.     }
  17.     public String getAddressWord(){
  18.         return addressWord;
  19.     }
  20.     public String getReason(){
  21.         return reason;
  22.     }
  24.     public boolean oneText(){
  25.         return reason != ONE_TEXT;
  26.     }
  27. }
  29. public class DataAdapter extends ArrayAdapter {
  30.     private int mColorResourceId;
  32.     public DataAdapter(@NonNull Context context, ArrayList<Data> resource, int ColorResourceId) {
  33.         super(context, 0, resource);
  34.         mColorResourceId = ColorResourceId;
  35.     }
  37.     @NonNull
  38.     @Override
  39.     public View getView(int position, @Nullable View convertView, @NonNull ViewGroup parent) {
  40.         View listItem = convertView;
  41.         if (listItem == null) {
  42.             listItem = LayoutInflater.from(getContext()).inflate(R.layout.list_item, parent, false);
  43.         }
  44.         Data currentWord = (Data) getItem(position);
  45.         TextView placeTextView = (TextView) listItem.findViewById(R.id.placetxt);
  46.         placeTextView.setText(currentWord.getPlaceWord());
  47.         TextView addressTextView = (TextView) listItem.findViewById(R.id.adddrestxt);
  48.         addressTextView.setText(currentWord.getAddressWord());
  49.         if (currentWord.oneText()) {
  50.             TextView reasonTextView = (TextView) listItem.findViewById(R.id.placetxt);
  51.             reasonTextView.setText(currentWord.getReason());
  52.         } else {
  53.             placeTextView.setVisibility(View.GONE);
  54.             addressTextView.setVisibility(View.GONE);
  55.         }
  56.         View textContainer = listItem.findViewById(R.id.list_item);
  57.         int color = ContextCompat.getColor(getContext(), mColorResourceId);
  58.         textContainer.setBackgroundColor(color);
  59.         return listItem;
  60.     }
  61. }

您可以在链接 1 中查看相关截图。

英文:

Now i want to list items in different categories ex: one of them hospitals and the one item must contain the name, the address and the phone number, I created this if statement in the adapter if the index of has one text invisible others but it didn't work with me well any help code

  1. public class Data {
  2. private String placeWord;
  3. private String addressWord;
  4. private String reason = ONE_TEXT;
  5. private static final String ONE_TEXT = &quot;ah&quot;;
  6. public Data(String mPlaceWord , String mAddressWord){
  7. placeWord = mPlaceWord;
  8. addressWord = mAddressWord;
  9. }
  10. public Data(String theReson){
  11. reason = theReson;
  12. }
  13. public String getPlaceWord(){
  14. return placeWord;
  15. }
  16. public String getAddressWord(){
  17. return addressWord;
  18. }
  19. public String getReason(){return reason;}
  20. public boolean oneText(){
  21. return  reason != ONE_TEXT;
  22. }
  1. public class DataAdapter extends ArrayAdapter {
  2.     private int mColorResourceId;
  4.     public DataAdapter(@NonNull Context context, ArrayList&lt;Data&gt; resource ,int ColorResourceId) {
  5.         super(context,0, resource);
  6.     mColorResourceId =  ColorResourceId ;
  7.     }
  8.     @NonNull
  9.     @Override
  10.     public View getView(int position, @Nullable View convertView, @NonNull ViewGroup parent) {
  11.         View listitem = convertView;
  12.         if( listitem == null){
  13.             listitem = LayoutInflater.from(getContext()).inflate(R.layout.list_item,parent,false);
  14.         }
  15.         Data currentword = (Data) getItem(position);
  16.         TextView pd = (TextView) listitem.findViewById(R.id.placetxt);
  17.         pd.setText(currentword.getPlaceWord());
  18.         TextView ad = (TextView) listitem.findViewById(R.id.adddrestxt);
  19.         ad.setText(currentword.getAddressWord());
  20.         if (currentword.oneText()){
  21.             TextView ps = (TextView) listitem.findViewById(R.id.placetxt);
  22.             ps.setText(currentword.getReason());
  23.         } else{
  24.             pd.setVisibility(View.GONE);
  25.             ad.setVisibility(View.GONE);
  26.        }
  27.         View textContainer = listitem.findViewById(R.id.list_item);
  28.         // Find the color that the resource ID maps to
  29.         int color = ContextCompat.getColor(getContext(), mColorResourceId);
  30.         // Set the background color of the text container View
  31.         textContainer.setBackgroundColor(color);
  32.         return listitem;
  33.     }
  34. }

答案1

得分: 0

使用一个"recycler view"，并将这个逻辑添加到它的适配器中。

英文:

Use a recycler view and add this logic in its adapter.

huangapple
  • 本文由 发表于 2020年10月2日 16:10:47
  • 转载请务必保留本文链接：https://go.coder-hub.com/64168213.html
  • android
  • android-arrayadapter
  • arraylist
  • custom-arrayadapter
  • java
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