英文:
show different list items on different catagories activities
问题
现在我想要在不同类别中列出项目，例如：其中一个类别是医院，其中一个项目必须包含名称、地址和电话号码。我在适配器中创建了这个if语句，如果索引具有一个文本不可见，其他的文本可见，但是它在我这里运行得不好，需要帮助。
以下是您提供的代码：
public class Data {
private String placeWord;
private String addressWord;
private String reason = ONE_TEXT;
private static final String ONE_TEXT = "ah";
public Data(String mPlaceWord, String mAddressWord){
placeWord = mPlaceWord;
addressWord = mAddressWord;
}
public Data(String theReason){
reason = theReason;
}
public String getPlaceWord(){
return placeWord;
}
public String getAddressWord(){
return addressWord;
}
public String getReason(){
return reason;
}
public boolean oneText(){
return reason != ONE_TEXT;
}
}
public class DataAdapter extends ArrayAdapter {
private int mColorResourceId;
public DataAdapter(@NonNull Context context, ArrayList<Data> resource, int ColorResourceId) {
super(context, 0, resource);
mColorResourceId = ColorResourceId;
}
@NonNull
@Override
public View getView(int position, @Nullable View convertView, @NonNull ViewGroup parent) {
View listItem = convertView;
if (listItem == null) {
listItem = LayoutInflater.from(getContext()).inflate(R.layout.list_item, parent, false);
}
Data currentWord = (Data) getItem(position);
TextView placeTextView = (TextView) listItem.findViewById(R.id.placetxt);
placeTextView.setText(currentWord.getPlaceWord());
TextView addressTextView = (TextView) listItem.findViewById(R.id.adddrestxt);
addressTextView.setText(currentWord.getAddressWord());
if (currentWord.oneText()) {
TextView reasonTextView = (TextView) listItem.findViewById(R.id.placetxt);
reasonTextView.setText(currentWord.getReason());
} else {
placeTextView.setVisibility(View.GONE);
addressTextView.setVisibility(View.GONE);
}
View textContainer = listItem.findViewById(R.id.list_item);
int color = ContextCompat.getColor(getContext(), mColorResourceId);
textContainer.setBackgroundColor(color);
return listItem;
}
}
您可以在链接 1 中查看相关截图。
英文:
Now i want to list items in different categories ex: one of them hospitals and the one item must contain the name, the address and the phone number, I created this if statement in the adapter if the index of has one text invisible others but it didn't work with me well any help code
public class Data {
private String placeWord;
private String addressWord;
private String reason = ONE_TEXT;
private static final String ONE_TEXT = "ah";
public Data(String mPlaceWord , String mAddressWord){
placeWord = mPlaceWord;
addressWord = mAddressWord;
}
public Data(String theReson){
reason = theReson;
}
public String getPlaceWord(){
return placeWord;
}
public String getAddressWord(){
return addressWord;
}
public String getReason(){return reason;}
public boolean oneText(){
return reason != ONE_TEXT;
}
public class DataAdapter extends ArrayAdapter {
private int mColorResourceId;
public DataAdapter(@NonNull Context context, ArrayList<Data> resource ,int ColorResourceId) {
super(context,0, resource);
mColorResourceId = ColorResourceId ;
}
@NonNull
@Override
public View getView(int position, @Nullable View convertView, @NonNull ViewGroup parent) {
View listitem = convertView;
if( listitem == null){
listitem = LayoutInflater.from(getContext()).inflate(R.layout.list_item,parent,false);
}
Data currentword = (Data) getItem(position);
TextView pd = (TextView) listitem.findViewById(R.id.placetxt);
pd.setText(currentword.getPlaceWord());
TextView ad = (TextView) listitem.findViewById(R.id.adddrestxt);
ad.setText(currentword.getAddressWord());
if (currentword.oneText()){
TextView ps = (TextView) listitem.findViewById(R.id.placetxt);
ps.setText(currentword.getReason());
} else{
pd.setVisibility(View.GONE);
ad.setVisibility(View.GONE);
}
View textContainer = listitem.findViewById(R.id.list_item);
// Find the color that the resource ID maps to
int color = ContextCompat.getColor(getContext(), mColorResourceId);
// Set the background color of the text container View
textContainer.setBackgroundColor(color);
return listitem;
}
}
答案1
得分: 0
使用一个"recycler view"，并将这个逻辑添加到它的适配器中。
英文:
Use a recycler view and add this logic in its adapter.
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