英文:
Use a while loop to count down numbers and finding the square root
问题
使用 while 循环如何对输入的数字进行平方根倒数计数？
例如，如果我运行代码并将第一个数字设置为 8，它会给我 8、7、6 等数字的平方根。
以下是迄今为止我的代码；目前，我只能得到第一个数字的平方根：
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int start;
int i;
System.out.print("输入一个正整数：");
start = scnr.nextInt();
if (start < 0) {
System.out.print("错误，请输入一个正整数");
} else {
i = start;
while (i != 0) {
double sqrt = Math.sqrt(i);
System.out.printf("%,4f ", sqrt);
i--;
}
}
}
英文:
How do I use a while loop to count down the input number with the square root?
For example, if I were to run the code and put the first number as 8 it would give me the square root of 8..7..6.. and so on.
Below is my code so far; right now, I only get the square root of the first number:
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int start;
int i;
System.out.print("Enter a positive integer: ");
start = scnr.nextInt();
if (start < 0) {
System.out.print("Error, enter a positive integer");
} else {
for(i = start; i != 0; i--); {
double sqrt = Math.sqrt(start);
start--;
System.out.printf("%,4f", sqrt);
}
}
}
答案1
得分: 2
这将实现你想要的功能：
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
System.out.print("输入一个正整数：");
int start = scnr.nextInt();
if (start < 0) {
System.out.print("错误，请输入一个正整数");
} else {
while (start != 0) {
double sqrt = Math.sqrt(start);
System.out.printf("%d: %,4f\n", start, sqrt);
start--;
}
}
}
输出结果：
输入一个正整数：36
36: 6.000000
35: 5.916080
34: 5.830952
33: 5.744563
32: 5.656854
31: 5.567764
30: 5.477226
29: 5.385165
28: 5.291503
27: 5.196152
26: 5.099020
25: 5.000000
24: 4.898979
23: 4.795832
22: 4.690416
21: 4.582576
20: 4.472136
19: 4.358899
18: 4.242641
17: 4.123106
16: 4.000000
15: 3.872983
14: 3.741657
13: 3.605551
12: 3.464102
11: 3.316625
10: 3.162278
9: 3.000000
8: 2.828427
7: 2.645751
6: 2.449490
5: 2.236068
4: 2.000000
3: 1.732051
2: 1.414214
1: 1.000000
英文:
This should do what you want:
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
System.out.print("Enter a positive integer: ");
int start = scnr.nextInt();
if (start < 0) {
System.out.print("Error, enter a positive integer");
} else {
while (start !=0) {
double sqrt = Math.sqrt(start);
System.out.printf("%d: %,4f\n", start, sqrt);
start--;
}
}
}
Output
Enter a positive integer: 36
36: 6.000000
35: 5.916080
34: 5.830952
33: 5.744563
32: 5.656854
31: 5.567764
30: 5.477226
29: 5.385165
28: 5.291503
27: 5.196152
26: 5.099020
25: 5.000000
24: 4.898979
23: 4.795832
22: 4.690416
21: 4.582576
20: 4.472136
19: 4.358899
18: 4.242641
17: 4.123106
16: 4.000000
15: 3.872983
14: 3.741657
13: 3.605551
12: 3.464102
11: 3.316625
10: 3.162278
9: 3.000000
8: 2.828427
7: 2.645751
6: 2.449490
5: 2.236068
4: 2.000000
3: 1.732051
2: 1.414214
1: 1.000000
答案2
得分: 1
如果您想实现为 while 循环
int i = start;
while(i >= 0){
//您的变量 i 正在递减，而不是 start，所以应该使用 Math.sqrt(i)
double sqrt = Math.sqrt(i);
System.out.println(sqrt);
i--;
}
<details>
<summary>英文:</summary>
If you want to implement as a while loop
int i = start;
while(i >= 0){
//your variable i is decrementing not start, so Math.sqrt(i)
double sqrt = Math.sqrt(i);
System.out.println(sqrt);
i--;
}
</details>
# 答案3
**得分**: 0
这里是你的解决方案，我也修复了缩进问题。在你的 if 语句之后有一个分号，使其变得无效。我按照你的要求实现了一个 while 循环，它会显示数字及其平方根，每次迭代递减1。让我知道这是否有效。
```java
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int start;
System.out.print("Enter a positive integer: ");
start = scnr.nextInt();
if (start < 0) {
System.out.print("Error, enter a positive integer");
}
while (start > 0) {
double sqrt = Math.sqrt(start);
System.out.println(start + " - " + sqrt);
start--;
}
}
英文:
Heres a solution for ya and i fixed the indentation as well. There was a semicolon after your if statement making it useless. I implemented a while loop as you requested which will display the number then its square root, decreasing by 1 each iteration. Let me know how this works.
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int start;
System.out.print("Enter a positive integer: ");
start = scnr.nextInt();
if (start < 0) {
System.out.print("Error, enter a positive integer");
}
while (start > 0) {
double sqrt = Math.sqrt(start);
System.out.println(start + " - " + sqrt);
start--;
}
}
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