英文:
Incorrect distance of point C from an arc AB on great circle
问题
以下是代码的翻译部分:
private static void pointToArcDistance(double thirdX, double thirdY, double startX, double startY,
double endX, double endY) {
double R = 6371000;
double φ1 = startX * Math.PI / 180;
double φ2 = endX * Math.PI / 180;
double Δφ = (endX - startX) * Math.PI / 180;
double Δλ = (endY - startY) * Math.PI / 180;
double a = Math.sin(Δφ / 2) * Math.sin(Δφ / 2) +
Math.cos(φ1) * Math.cos(φ2) *
Math.sin(Δλ / 2) * Math.sin(Δλ / 2);
double c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a));
double d13 = R * c; // distance between start & endPoint in meters
double brng12 = bearing(startX, startY, endX, endY);
double brng13 = bearing(startX, startY, thirdX, thirdY);
double δ13 = d13 / R;
double dXt = Math.asin(Math.sin(δ13) * Math.sin(brng13 - brng12)) * R;
System.out.println("切线距离(CD):" + dXt);
}
private static double bearing(double lat1, double long1, double lat2, double long2) {
double y = Math.sin(long2 - long1) * Math.cos(lat2);
double x = Math.cos(lat1) * Math.sin(lat2) -
Math.sin(lat1) * Math.cos(lat2) * Math.cos(long2 - long1);
double polarDegrees = toDegrees(Math.atan2(y, x));
return polarDegrees < 0 ? polarDegrees + 360 : polarDegrees;
}
英文:
Im getting incorrect length of CD where D marks the projection of third point C on arc AB:
Input to above code::
startX,startY- start point's coordinates of the arc--> (48.1388, 11.54988)
endX,endY-end point's coordinates of arc--> (48.139, 11.54988)
thirdX,thirdY- coordinated of point C away from arc--> (48.1389, 11.5496)
dXt is coming to be -13.41654587971497 meters but the expected value is 31.16949
I've written the code based on the equations I found: here
I am unable to find the cause of incorrect value, please help.Thanks.
<pre><code>
private static void pointToArcDistance(double thirdX, double thirdY, double startX, double startY,
double endX, double endY) {
double R = 6371000;
double φ1 = startX * Math.PI / 180;
double φ2 = endX * Math.PI / 180;
double Δφ = (endX - startX) * Math.PI / 180;
double Δλ = (endY - startY) * Math.PI / 180;
double a = Math.sin(Δφ / 2) * Math.sin(Δφ / 2) +
Math.cos(φ1) * Math.cos(φ2) *
Math.sin(Δλ / 2) * Math.sin(Δλ / 2);
double c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a));
double d13 = R * c; // distance between start & endPoint in meters
double brng12 = bearing(startX, startY, endX, endY);
double brng13 = bearing(startX, startY, thirdX, thirdY);
double δ13 = d13 / R;
double dXt = Math.asin(Math.sin(δ13) * Math.sin(brng13 - brng12)) * R;
System.out.println("tangent distance(CD)::" + dXt);
}
private static double bearing(double lat1, double long1, double lat2, double long2) {
double y = Math.sin(long2 - long1) * Math.cos(lat2);
double x = Math.cos(lat1) * Math.sin(lat2) -
Math.sin(lat1) * Math.cos(lat2) * Math.cos(long2 - long1);
double polarDegrees = toDegrees(Math.atan2(y, x));
return polarDegrees < 0 ? polarDegrees + 360 : polarDegrees;
}
</code></pre>
答案1
得分: 1
你在这里将弧度转换为角度:
double polarDegrees = toDegrees(Math.atan2(y, x));
但接下来的计算需要使用弧度。
所以只需移除 toDegrees
。
英文:
You transform radians to degrees here:
double polarDegrees = toDegrees(Math.atan2(y, x));
but the next calculations need radians.
So just remove toDegrees
答案2
得分: 0
找到点到弧的距离:
- 首先,找到弧所隐含的椭圆的中心
- 使用 atan2 计算点到弧的角度
- 使用 cos(angle) * r1、sin(angle) * r2 计算与椭圆的 x、y 截距
- 使用从 x、y 截距到点的距离公式计算距离
英文:
To find the distance from a point to an arc:
- First, find the center of the oval implied by the arc
- Find the angle to the point using atan2
- Find the x,y intercept with your oval using cos(angle) * r1, sin(angle) * r2
- Use the distance formula from the x,y intercept to the point
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