英文:
How to sort a table created with Formatter?
问题
我创建了一个从文件中读取文本、计算每个单词出现次数并将所有内容放入使用Formatter创建的表格的应用程序。现在我想按单词的出现次数对表格进行排序。以下是迄今为止的代码：
package com.example.antonpaarapplication;import java.io.IOException;import java.nio.file.Files;import java.nio.file.Paths;import java.util.*;public class Application {// 初始化应用程序的函数。public void run() {System.out.println("您想处理整个文件(1)还是仅处理特定行(2)？");choice();}// 选择是一次性处理整个文件还是仅处理选择的特定文件的函数。public void choice() {Scanner scanner = new Scanner(System.in);int number = scanner.nextInt();switch (number) {case 1:System.out.println("\n已输入数字1，正在处理整个文件。\n");processWholeFile();break;case 2:System.out.println("\n已输入数字2，请指定要处理的行。\n");processSpecificLines();break;default:System.out.println("无效，请重试。");choice();}}// 处理整个文件的函数。public void processWholeFile() {Map<String, Integer> stringMap = new HashMap<>();Formatter formatter = new Formatter();List<String> lines = readFile();String string = String.join(" ", lines);String[] arr = string.split(" ");for (String s : arr) {if (stringMap.containsKey(s)) {stringMap.put(s, stringMap.get(s) + 1);} else {stringMap.put(s, 1);}}formatter.format("%20s %20s\n\n", "单词", "出现次数");for (Map.Entry<String, Integer> mapEntry : stringMap.entrySet()) {if (mapEntry.getKey().substring(0, 1).equals("1")) {formatter.format("%20s %20s\n", mapEntry.getKey(), mapEntry.getValue());} else {formatter.format("%20s %15s\n", mapEntry.getKey(), mapEntry.getValue());}}System.out.println(formatter);}// 处理文件特定部分的函数。public void processSpecificLines() {}// 读取"data.txt"的内容。public List<String> readFile() {List<String> lines = new ArrayList<>();try {lines = Files.readAllLines(Paths.get(System.getProperty("user.dir"), "src", "main", "resources", "data.txt"));} catch (IOException e) {throw new RuntimeException(e);}return lines;}public static void main(String[] args) {Application app = new Application();app.run();}}
我尝试在Google上搜索这个问题，但似乎要么不可能实现，要么没有人想过这个问题，因为我找不到相关信息。
英文:
I made an application that reads text from a file, counts each word, and puts everything into a table created with Formatter. Now I would like to sort the table by the number Occurrences per word. Here is my code so far:
java
package com.example.antonpaarapplication;import java.io.IOException;import java.nio.file.Files;import java.nio.file.Paths;import java.util.*;public class Application {//Function for Initializing the Application.public void run() {System.out.println("Would you like to process the entire file(1) or just specific lines(2)?");choice();}//Function for choosing whether to process the entire file at once or only select specific files to be processed.public void choice() {Scanner scanner = new Scanner(System.in);int number = scanner.nextInt();switch (number) {case 1:System.out.println("\nNumber 1 has been entered, processing whole file.\n");processWholeFile();break;case 2:System.out.println("\nNumber 2 has been entered, please specify lines to be processed. \n");processSpecificLines();break;default:System.out.println("Invalid, please try again.");choice();}}//Function for processing the entire File.public void processWholeFile() {Map<String, Integer> stringMap = new HashMap<String, Integer>();Formatter formatter = new Formatter();List<String> lines = readFile();String string = String.join(" ", lines);String[] arr = string.split(" ");for (String s : arr) {if (stringMap.containsKey(s)) {stringMap.put(s, stringMap.get(s) + 1);} else {stringMap.put(s, 1);}}formatter.format("%20s %20s\n\n", "Word", "Occurence");for (Map.Entry<String, Integer> mapEntry : stringMap.entrySet()) {if (mapEntry.getKey().substring(0, 1).equals("1")) {formatter.format("%20s %20s\n", mapEntry.getKey(), mapEntry.getValue());} else {formatter.format("%20s %15s\n", mapEntry.getKey(), mapEntry.getValue());}}System.out.println(formatter);}//Function for processing specific parts of the file.public void processSpecificLines() {}//Reads the contents of the "data.txt".public List<String> readFile() {List<String> lines = new ArrayList<>();try {lines = Files.readAllLines(Paths.get(System.getProperty("user.dir"), "src", "main", "resources", "data.txt"));} catch (IOException e) {throw new RuntimeException(e);}return lines;}public static void main(String[] args) {Application app = new Application();app.run();}}
I tried googling the problem, but it seems like this either not possible or nobody has every thought about it, as I can't find anything about it.
答案1
得分: 1
问题不在于 Formatter 本身，而在于在格式化之前如何存储数据，使用了一个不维护任何顺序的 HashMap。您可以改用一个可排序的集合，例如：
List<Map.Entry<String, Integer>> sortedList = new ArrayList<>(stringMap.entrySet());sortedList.sort(Map.Entry.<String, Integer>comparingByValue().reversed());formatter.format("%20s %20s\n\n", "Word", "Occurrence");for (Map.Entry<String, Integer> mapEntry : sortedList) {if (mapEntry.getKey().substring(0, 1).equals("1")) {formatter.format("%20s %20s\n", mapEntry.getKey(), mapEntry.getValue());} else {formatter.format("%20s %15s\n", mapEntry.getKey(), mapEntry.getValue());}}
英文:
The problem is not with the Formatter itself, but how you're storing the data before formatting it, using a HashMap which doesn't maintain any ordering. You could use a sortable collection instead, like:
List<Map.Entry<String, Integer>> sortedList = new ArrayList<>(stringMap.entrySet());sortedList.sort(Map.Entry.<String, Integer>comparingByValue().reversed());formatter.format("%20s %20s\n\n", "Word", "Occurrence");for (Map.Entry<String, Integer> mapEntry : sortedList) {if (mapEntry.getKey().substring(0, 1).equals("1")) {formatter.format("%20s %20s\n", mapEntry.getKey(), mapEntry.getValue());} else {formatter.format("%20s %15s\n", mapEntry.getKey(), mapEntry.getValue());}}
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