英文:
What is the c# equivalent to Java's GeneralPath?
问题
以下是翻译好的内容：
"Say I need to covert this java program into a C# program.
What is the C# equivalent to java's GeneralPath found in the package java.awt.geom?"
英文:
Say I need to covert this java program into a C# program.
What is the C# equivalent to java's GeneralPath found in the package java.awt.geom?
答案1
得分: 2
以下是翻译好的内容：
等效的（如果使用 System.Drawing）是：
System.Drawing.Drawing2D.GraphicsPath
你可以这样绘制线条：
var gp1 = new GraphicsPath();
gp1.AddLines(new Point[]
{
new Point(50, 10),
new Point(70, 80),
new Point(90, 40),
new Point(10, 40),
new Point(50, 80)
});
gp1.CloseFigure();
e.Graphics.DrawPath(new Pen(new SolidBrush(Color.Red)), gp1);
GraphisPath 没有二次贝塞尔曲线，但你可以将其拟合为三次贝塞尔曲线。以下是执行此操作的扩展方法：
public static class GraphicsPathExtensions
{
public static void AddQuadraticBezier(
this GraphicsPath graphicsPath, PointF start, PointF ctrl, PointF end)
{
var c1 = new PointF(start.X, start.Y);
c1.X += (2.0f / 3.0f) * (ctrl.X - start.X);
c1.Y += (2.0f / 3.0f) * (ctrl.Y - start.Y);
var c2 = new PointF(ctrl.X, ctrl.Y);
c2.X += (end.X - ctrl.X) / 3.0f;
c2.Y += (end.Y - ctrl.Y) / 3.0f;
graphicsPath.AddBezier(start, c1, c2, end);
}
public static void AddQuadraticBezier(
this GraphicsPath graphicsPath, Point start, Point ctrl, Point end)
{
graphicsPath.AddQuadraticBezier(
new PointF(start.X, start.Y),
new PointF(ctrl.X, ctrl.Y),
new PointF(end.X, end.Y));
}
}
你可以这样调用它：
var gp6 = new GraphicsPath();
gp6.AddQuadraticBezier(
new Point(120, 180),
new Point(150, 120),
new Point(180, 180));
gp6.CloseFigure();
e.Graphics.DrawPath(new Pen(new SolidBrush(Color.Red)), gp6);
以下是所有示例的示例：
var gp7 = new GraphicsPath();
gp7.AddBezier(
new Point(220, 150),
new Point(240, 130),
new Point(280, 160),
new Point(300, 140));
gp7.AddLine(
new Point(300, 140),
new Point(300, 180));
gp7.AddQuadraticBezier(
new Point(300, 180),
new Point(260, 160),
new Point(220, 180));
gp7.CloseFigure();
e.Graphics.DrawPath(new Pen(new SolidBrush(Color.Red)), gp7);
英文:
The equivalent (if using System.Drawing) is:
System.Drawing.Drawing2D.GraphicsPath
You can do lines as so:
var gp1 = new GraphicsPath();
gp1.AddLines(new Point[]
{
new Point(50, 10),
new Point(70, 80),
new Point(90, 40),
new Point(10, 40),
new Point(50, 80)
});
gp1.CloseFigure();
e.Graphics.DrawPath(new Pen(new SolidBrush(Color.Red)), gp1);
GraphisPath does not have a Quadratic Bezier, but you can fit it in to a Cubic Bezier. Here is an extension to do that:
public static class GraphicsPathExtensions
{
public static void AddQuadraticBezier(
this GraphicsPath graphicsPath, PointF start, PointF ctrl, PointF end)
{
var c1 = new PointF(start.X, start.Y);
c1.X += (2.0f / 3.0f) * (ctrl.X - start.X);
c1.Y += (2.0f / 3.0f) * (ctrl.Y - start.Y);
var c2 = new PointF(ctrl.X, ctrl.Y);
c2.X += (end.X - ctrl.X) / 3.0f;
c2.Y += (end.Y - ctrl.Y) / 3.0f;
graphicsPath.AddBezier(start, c1, c2, end);
}
public static void AddQuadraticBezier(
this GraphicsPath graphicsPath, Point start, Point ctrl, Point end)
{
graphicsPath.AddQuadraticBezier(
new PointF(start.X, start.Y),
new PointF(ctrl.X, ctrl.Y),
new PointF(end.X, end.Y));
}
}
You could call it as so:
var gp6 = new GraphicsPath();
gp6.AddQuadraticBezier(
new Point(120, 180),
new Point(150, 120),
new Point(180, 180));
gp6.CloseFigure();
e.Graphics.DrawPath(new Pen(new SolidBrush(Color.Red)), gp6);
Here is an example of all of them:
var gp7 = new GraphicsPath();
gp7.AddBezier(
new Point(220, 150),
new Point(240, 130),
new Point(280, 160),
new Point(300, 140));
gp7.AddLine(
new Point(300, 140),
new Point(300, 180));
gp7.AddQuadraticBezier(
new Point(300, 180),
new Point(260, 160),
new Point(220, 180));
gp7.CloseFigure();
e.Graphics.DrawPath(new Pen(new SolidBrush(Color.Red)), gp7);
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