英文:
I am checking for pallindrome string..Why does this always print yes
问题
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String A = sc.next();
StringBuffer a1 = new StringBuffer();
a1.append(A);
System.out.println(a1.equals(a1.reverse()) ? "Yes" : "No");
}
英文:
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
String A=sc.next();
StringBuffer a1 = new StringBuffer();
a1.append(A);
System.out.println(a1.equals(a1.reverse())?"Yes":"No");
}
答案1
得分: 1
这将始终返回 yes，因为 a1.reverse() 返回原始的 StringBuffer 对象，它与 a1 相同。如果您想要比较字符串，您需要从 StringBuffer 对象生成字符串：
public static void main (String[] args) {
Scanner sc = new Scanner(System.in);
String A = sc.next();
StringBuffer a1 = new StringBuffer();
a1.append(A);
System.out.println(a1.toString().equals(a1.reverse().toString()) ? "Yes" : "No");
}
英文:
This will always return yes as a1.reverse() returns original StringBuffer object which is same as a1. If you want to compare string, you have to generate string from stringbuffer object:
public static void main (String[] args) {
Scanner sc=new Scanner(System.in);
String A=sc.next();
StringBuffer a1 = new StringBuffer();
a1.append(A);
System.out.println(a1.toString().equals(a1.reverse().toString())?"Yes":"No");
}
答案2
得分: 0
是的，通过首先将其转换为字符串，您将能够比较它们。否则，您将比较它们的地址（StringBuffer地址），在这两种情况下都是相同的。
英文:
Yes by converting it into a string first you would be able to compare them .
Otherwise you would be comparing there address(StringBuffer address),which is same is case of both.
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