英文:
add data after every 2nd element in an array
问题
我想在每两个元素之后向数组中添加对象/数据...为了更清楚起见，我将使用一个简单的示例
我有一个数组列表：
List<Object> list = new ArrayList<>();list.add("messi");list.add("ronaldo");list.add("rooney");list.add("pogba");list.add("hazard");print(list);//输出：[messi，ronaldo，rooney，pogba，hazard]
我想要的是：
//[messi，ronaldo，DATA，rooney，pogba，DATA，hazard]
我如何实现这个目标。
在每两个元素之后添加数据到数组中。
英文:
I want to add object/data in an array after every 2nd element ....just for making more clear I am going to use a simple example
I have arrayList of :
List<Object> list = new ArrayList<>();list.add("messi");list.add("ronaldo");list.add("rooney");list.add("pogba");list.add("hazard");print(list);//output : [messi, ronaldo, rooney, pogba,hazard]
What I want is:
//[messi, ronaldo, DATA, rooney, pogba, DATA, hazard]
how I can achieve this.
Adding data in an array after every 2nd element.
答案1
得分: 3
通过维护一个计数器。public class Main {public static void main(String[] args) {List<Object> list = new ArrayList<>();list.add("messi");list.add("ronaldo");list.add("rooney");list.add("pogba");list.add("hazard");int counter = 0;List<Object> data = new ArrayList<>();for (Object obj : list) {data.add(obj);counter = counter + 1;if (counter % 2 == 0)data.add("DATA");}for (Object obj : data)System.out.println(obj);}}
英文:
By maintaining a counter.
public class Main {public static void main(String[] args) {List<Object> list = new ArrayList<>();list.add("messi");list.add("ronaldo");list.add("rooney");list.add("pogba");list.add("hazard");int counter = 0 ;List<Object> data = new ArrayList<>();for(Object obj : list){data.add(obj);counter = counter + 1;if(counter%2 == 0)data.add("DATA");}for(Object obj : data)System.out.println(obj);}}
答案2
得分: 2
所以，你可以做的是创建一个新的列表来存储带有新对象的旧数据：
List<Object> list = new ArrayList<>();List<Object> newlist = new ArrayList<>();list.add("messi");list.add("ronaldo");list.add("rooney");list.add("pogba");list.add("hazard");for (int i = 0; i < list.size(); i++) {if (i % 2 == 0) {// 在每两个项目后添加DATAnewlist.add(data);}newlist.add(list.get(i));}
请有人进行格式化，因为我是从手机上编写的。
英文:
So, you can do is create a new list to store the old data with new object:
List<Object> list = new ArrayList<>();List<Object> newlist = new ArrayList<>();list.add("messi");list.add("ronaldo");list.add("rooney");list.add("pogba");list.add("hazard");for(int i = 0; i < list.size(); i++) {if(i%2==0) {// Add DATA after 2 itemsnewlist.add(data);}newlist.add(list.get(i));}
Please someone format since I'm writing from my phone.
答案3
得分: 0
class sample {public static void main(String[] args) {List<Object> list = new ArrayList<>();sample.addList("messi", list);sample.addList("ronaldo", list);sample.addList("rooney", list);sample.addList("pogba", list);sample.addList("hazard", list);System.out.println(list);}private static void addList(String value, List<Object> objects) {if (!objects.isEmpty() && (objects.size() % 3 == 2)) {objects.add("Data");}objects.add(value);}}
可以创建一个如上所述的实用方法。
每次在添加元素之前，检查一下是否 list.size() % 3 == 2，如果是，则添加额外的元素。
这会对你有所帮助。
英文:
class sample {public static void main(String[] args) {List<Object> list = new ArrayList<>();sample.addList("messi", list);sample.addList("ronaldo", list);sample.addList("rooney", list);sample.addList("pogba", list);sample.addList("hazard", list);System.out.println(list);}private static void addList(String value, List<Object> objects) {if (!objects.isEmpty() && (objects.size() % 3 == 2)) {objects.add("Data");}objects.add(value);}}
You can create one utility method as mentioned above.
For every time before adding element check that if list.size() % 3 == 2 then add extra element.
This will help you.
答案4
得分: 0
看一下所需的输出和插入的DATA值的索引：
[messi, ronaldo, DATA, rooney, pogba, DATA, hazard]0 1 2 3 4 5 6
DATA值放在索引2、5、8、11等处。
这意味着这是一个简单的for循环，调用add(int index, E element)：
List<Object> list = new ArrayList<>();list.add("messi");list.add("ronaldo");list.add("rooney");list.add("pogba");list.add("hazard");System.out.println(list);for (int i = 2; i < list.size(); i += 3) {list.add(i, "DATA");}System.out.println(list);
输出
[messi, ronaldo, rooney, pogba, hazard][messi, ronaldo, DATA, rooney, pogba, DATA, hazard]
英文:
Look at the desired output and the indexes of the inserted DATA values:
[messi, ronaldo, DATA, rooney, pogba, DATA, hazard]0 1 2 3 4 5 6
The DATA values go in index 2, 5, 8, 11, ...
Which means it's a simple for loop calling add(int index, E element):
List<Object> list = new ArrayList<>();list.add("messi");list.add("ronaldo");list.add("rooney");list.add("pogba");list.add("hazard");System.out.println(list);for (int i = 2; i < list.size(); i += 3) {list.add(i, "DATA");}System.out.println(list);
Output
[messi, ronaldo, rooney, pogba, hazard][messi, ronaldo, DATA, rooney, pogba, DATA, hazard]
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