Hibernate:多个表,同一个对象

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英文:

Hibernate: Multiple tables, same object

问题

我正在尝试编写一个简单的应用程序,其中包含一个表,用于跟踪每个用户所做的付款,以及第二个表,其中包含每个用户支付的总金额(所有付款的总和)。目前,这两个表具有相同的字段(firstName、lastName、amount),并且我已经从同一个Java类进行了映射,但我在将该类映射到多个表时遇到了问题。是否有任何简单的解决方案?

@Entity
@Table(name="Payment")
public class Payment{

  @Id
  @GeneratedValue(strategy = GenerationType.AUTO)
  private Long id;

  @Column
  @NotNull
  private String firstName;

  @Column
  @NotNull
  private String lastName;

  @Column
  @NotNull
  private double amount;

  ... 构造函数getter和setter
}
英文:

I am trying to write a simple app that contains one table that keeps track of payments each user has made and a second table that contains total amount each user has paid (sum of all payments). Currently, both tables have the same fields (firstName, lastName, amount) and I have mapped them from the same Java class
and I have trouble mapping that class to multiple tables. Is there any simple solution to this?

@Entity
@Table(name="Payment")
public class Payment{

  @Id
  @GeneratedValue(strategy = GenerationType.AUTO)
  private Long id;

  @Column
  @NotNull
  private String firstNname;

  @Column
  @NotNull
  private String lastNname;

  @Column
  @NotNull
  private double amount;

... Constructor, getters and setters
}

答案1

得分: 1

你可以尝试使用 @SecondaryTable annotation

类似于以下内容:

@Entity
@Table(name = "MY_PAYMENT")
@SecondaryTable(name = "MY_PAYMENT_DETAILS",
    pkJoinColumns = @PrimaryKeyJoinColumn(name = "pd_payment_id"))
public class Payment {

   @Id
   @Column(name = "p_id")
   private Long id;
   
   @Column(name = "p_first_name")
   private String firstNname;

   // ...
   
   @Column(name = "pd_amount", table = "MY_PAYMENT_DETAILS")
   private double amount;
}

这假设你有以下的数据库模式:

create table MY_PAYMENT
(
   p_id number,
   p_first_name varchar(200),
   CONSTRAINT MY_PAYMENT_PK PRIMARY KEY(p_id)
);

create table MY_PAYMENT_DETAILS
(
   pd_payment_id number,
   pd_amount number,
   CONSTRAINT MY_PAYMENT_DETAILS_PK PRIMARY KEY(pd_payment_id),
   CONSTRAINT MY_PAYMENT_DETAILS_FK foreign key(pd_payment_id) references MY_PAYMENT(p_id)
);

还可以参考 hibernate 文档的这个部分。

英文:

You can try to use @SecondaryTable annotation.

Something like this:

@Entity
@Table(name = "MY_PAYMENT")
@SecondaryTable(name = "MY_PAYMENT_DETAILS",
    pkJoinColumns = @PrimaryKeyJoinColumn(name = "pd_payment_id"))
public class Payment {

   @Id
   @Column(name = "p_id")
   private Long id;
   
   @Column(name = "p_first_name")
   private String firstNname;

   // ...
   
   @Column(name = "pd_amount", table = "MY_PAYMENT_DETAILS")
   private double amount;
}

This is assumed that you have the following schema:

create table MY_PAYMENT
(
   p_id number,
   p_first_name varchar(200),
   CONSTRAINT MY_PAYMENT_PK PRIMARY KEY(p_id)
);

create table MY_PAYMENT_DETAILS
(
   pd_payment_id number,
   pd_amount number,
   CONSTRAINT MY_PAYMENT_DETAILS_PK PRIMARY KEY(pd_payment_id),
   CONSTRAINT MY_PAYMENT_DETAILS_FK foreign key(pd_payment_id) references MY_PAYMENT(p_id)
);

See also this section of hibernate documentation.

答案2

得分: 1

你需要:

@MappedSuperclass
public class ClassWithTheFields{
\\没有用 @Entity 注解
@Id private Integer Id;
...
}

@Entity
public class EntityClass extends ClassWithTheFields{}

@Entity
public class AnotherEntityClass extends ClassWithTheFields{}

这样,继承 ClassWithTheFields 的这两个类将拥有相同的字段,但会映射到不同的数据库表格。

你只需要将所有共同的字段放在一个带有 @MappedSuperclass 注解的类中,但不要用 @Entity 注解标注它,然后在其他带有 @Entity 注解的类中继承这个类。

英文:

You need:

@MappedSuperclass
public class ClassWithTheFields{
\\Not annotated with @Entity
@Id private Integer Id;
...
}

@Entity
public class EntityClass extends ClassWithTheFields{}

@Entity
public class AnotherEntityClass extends ClassWithTheFields{}

This way, both classes extending ClassWithTheFields will have the same fields, but will be mapping different tables.

You just need to put all the common fields in a class annotated with @MappedSuperclass, but not@Entity, and then extend this class in other classes annotated with @Entity.

答案3

得分: 1

你应该选择 @MappedSuperclass。这对你来说是最简单的选择。

英文:

You should go with @MappedSuperclass. It's the easiest choice for you.

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  • 本文由 发表于 2020年9月12日 19:01:00
  • 转载请务必保留本文链接:https://go.coder-hub.com/63859618.html
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