英文:
Exception in thread "main" :0
问题
import java.util.*;
public class Windchill {
public static void main(String[] args) {
double t = Double.parseDouble(args[0]);
double v = Double.parseDouble(args[1]);
double w = 35.74 + 0.6215 * t + (0.4275 * t - 35.75) * Math.pow(v, 0.16);
System.out.println("Windchill =" + w);
}
}
一直收到这个错误,不确定为什么,有人可以帮忙吗:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0
at Windchill.main(Windchill.java:5)
英文:
import java.util.*;
public class Windchill {
public static void main(String[]args)
{
double t=Double.parseDouble(args[0]);
double v=Double.parseDouble(args[1]);
double w=35.74+0.6215*t+(0.4275*t-35.75)*Math.pow(v, 0.16);
System.out.println("Windchill =" + w);
}
}
Keep getting this error and unsure why can someone help:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0
at Windchill.main(Windchill.java:5)
答案1
得分: 1
这是因为你尝试从一个空的 String[]
中获取值。
在这一行
double t = Double.parseDouble(args[0]);
你尝试获取 args[0]
,但在运行程序时你有提供任何 args
吗?点击此链接查看如何操作。
如果没有提供,你试图从一个大小为 0 的数组中获取第一个元素,这超出了数组的范围,因此会出现 ArrayIndexOutOfBoundsException
。
英文:
This happens because you're trying to get a value from an empty String[]
.
On this line
double t = Double.parseDouble(args[0]);
You try to get args[0]
but are you giving any args
when you run the program? Check this link to see how to do it.
If you're not, you're trying to get 1 item from an array with size = 0
which is more than it has, hence ArrayIndexOutOfBoundsException
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