问题

有一个带有格式的字符串：

`今天是 %s，气温为 %d℉。`

如何使用 Java 中的正则表达式提取 %s 值和 %d 值？

例如：

```java
输入：今天是星期日，气温为 70℉
输出：星期日，70

<details>
<summary>英文:</summary>

There is a string with formatter:

`Today is %s with degree %d℉.`

How can I pick %s value and %d value by using regex in java?

For Example:

Input: Today is Sunday with degree 70℉
Output: Sunday, 70

</details>


# 答案1
**得分**: 1

这里有一个 [Java 示例](https://regex101.com/r/BFBg6I/1)：

```java
import java.util.regex.Matcher;
import java.util.regex.Pattern;

final String regex = "今天是 (\\w+)，气温 (\\d+)℉";
final String string = "今天是星期日，气温 70℉";

final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE | Pattern.UNICODE_CHARACTER_CLASS);
final Matcher matcher = pattern.matcher(string);

while (matcher.find()) {
    System.out.println("完整匹配: " + matcher.group(0));
    for (int i = 1; i <= matcher.groupCount(); i++) {
        System.out.println("第 " + i + " 组: " + matcher.group(i));
    }
}

import java.util.regex.Matcher;
import java.util.regex.Pattern;

final String regex = "Today is (\\w+) with degree (\\d+)℉";
final String string = "Today is Sunday with degree 70℉";

final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE | Pattern.UNICODE_CHARACTER_CLASS);
final Matcher matcher = pattern.matcher(string);

while (matcher.find()) {
    System.out.println("Full match: " + matcher.group(0));
    for (int i = 1; i <= matcher.groupCount(); i++) {
        System.out.println("Group " + i + ": " + matcher.group(i));
    }
}