英文:
Regex to select groups between dots without brackets
问题
以下是您要翻译的部分：
我有这样的字符串：test.as123[13].tdfvParent.child1test.d12[0].asdf我需要一个正则表达式，可以给我匹配到这样的组：- test, as123, tdfv- Parent, child1- test, d12, asdf所以我需要在句点处分割这些组，并删除名称中的括号。我尝试使用否定字符类，就像这样：([^\W\d]+)但结果会是"child"而不是"child1"。我的问题是，我不确定如何忽略特定的字符串`\[\d\]`并继续匹配`\d`。我尝试使用负向先行断言，但我觉得我做错了什么。这是我的尝试：\w+(?!\[[0-9]*?\])这确实匹配了，例如：- test, 13, tdfv
请注意，我已经删除了不需要的部分，只返回了翻译好的内容。如果您有任何其他问题，请随时提出。
英文:
I got Strings like this:
test.as123[13].tdfvParent.child1test.d12[0].asdf
I need a regex which gets me groups like this:
- test, as123, tdfv
- Parent, child1
- test, d12, asdf
So I need to divide the groups on the dot and also remove the brackets in its name.
I tried using negation like this:
([^\W\d]+)
But there will be child as result and not child1.
My problem is that I'm not sure on how to ignore the specific String \[\d\] and keep on matching \d
I tried using negative lookahead, but I think I'm doing something wrong.
Here's my attemp:
\w+(?!\[[0-9]*?\])
This does match for example:
- test, 13, tdfv
答案1
得分: 3
// You can remove all occurrences of digits inside square brackets and then split on a dot:.replaceAll("\\[\\d+]", "").split("\\.")// Or, you may directly split on the `(?:\\[\\d+])?\\.` pattern:.split("(?:\\[\\d+])?\\.")// It matches// - `(?:\\[\\d+])?` - an optional occurrence of a `[`, 1+ digits, `]`// - `\\.` - a dot.// See the [Java demo online][1]:String s = "test.as123[13].tdfv";String results[] = s.replaceAll("\\[\\d+]", "").split("\\.");System.out.println(Arrays.toString(results));// => [test, as123, tdfv]String results2[] = s.split("(?:\\[\\d+])?\\.");System.out.println(Arrays.toString(results2));// => [test, as123, tdfv]
英文:
You can remove all occurrences of digits inside square brackets and then split on a dot:
.replaceAll("\\[\\d+]", "").split("\\.")
Or, you may directly split on the (?:\[\d+])?\. pattern:
.split("(?:\\[\\d+])?\\.")
It matches
(?:\[\d+])?- an optional occurrence of a[, 1+ digits,]\.- a dot.
See the Java demo online:
String s = "test.as123[13].tdfv";String results[] = s.replaceAll("\\[\\d+]", "").split("\\.");System.out.println(Arrays.toString(results));// => [test, as123, tdfv]String results2[] = s.split("(?:\\[\\d+])?\\.");System.out.println(Arrays.toString(results2));// => [test, as123, tdfv]
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