英文:
How do I convert an array of integers to binary?
问题
for (int i = 0; i < n; i++) {arr[i] = scanner.nextInt();}String[] bin = new String[n];for (int i = 0; i < n; i++) {bin[i] = Integer.toBinaryString(arr[i]);}
上述代码将整数数组转换为一个字符串数组（包含输入整数的二进制格式），但有一个注意事项。
例如：
如果输入数组为：2 3 7 10
二进制字符串数组将为：
10
11
111
1010
但我希望输出数组如下所示：
0010
0011
0111
1010
#2
如果输入数组为：2 10 20
二进制字符串数组将为：
10
1010
10100
但我希望输出数组如下所示：
00010
01010
10100
<details><summary>英文:</summary>
for (int i = 0; i < n; i++) {
arr[i] = scanner.nextInt();
}
String[] bin = new String[n];
for (int i = 0; i < n; i++) {
bin[i] = Integer.toBinaryString(arr[i]);
}
The above code will convert the the whole array of integers into an array of `String`s (containing binary format of the input string), but there is a caveat.For Example:<br/>If the input array is: 2 3 7 10<br/>The binary string array will be:10<br/>11<br/>111<br/>1010<br/>But I want the output array to be like the following:<br/>0010<br/>0011<br/>0111<br/>1010<br/>#2<br/>If the input array is: 2 10 20<br/>The binary string array will be:<br/>10<br/>1010<br/>10100<br/>But I want the output array to be like the following:<br/>00010<br/>01010<br/>10100<br/></details># 答案1**得分**: 4要使所有二进制字符串的长度与最长“字符串”的长度匹配，您可以首先找到最长的长度，然后使用 `String＃format` 和 `String＃replace` 进行零填充。```javaint maxLen = 0;for (int i = 0; i < n; i++) {bin[i] = Integer.toBinaryString(arr[i]);maxLen = Math.max(maxLen, bin[i].length());}for (int i = 0; i < n; i++) {if (bin[i].length() != maxLen)bin[i] = String.format("%" + maxLen + "s", bin[i]).replace(' ', '0');System.out.println(bin[i]);}
英文:
To have all of the binary strings match the length of the longest String, you can first find the longest length and then use String#format and String#replace to pad with zeroes.
int maxLen = 0;for (int i = 0; i < n; i++) {bin[i] = Integer.toBinaryString(arr[i]);maxLen = Math.max(maxLen, bin[i].length());}for (int i = 0; i < n; i++) {if (bin[i].length() != maxLen)bin[i] = String.format("%" + maxLen + "s", bin[i]).replace(' ', '0');System.out.println(bin[i]);}
答案2
得分: 1
你可以首先计算数组的最大二进制字符串长度，然后使用 Collections.nCopies 在每个二进制字符串表示之前添加所需的额外的 0。
int mx = 0;for (int i = 0; i < n; i++) {bin[i] = Integer.toBinaryString(arr[i]);mx = Math.max(mx, bin[i].length());}for (int i = 0; i < n; i++) {bin[i] = String.join("", Collections.nCopies(mx - bin[i].length(), "0")) + bin[i];}
英文:
You can first calculate the max binary string length of array then use Collections.nCopies to add extra 0 needed before string representation of binary string each.
int mx = 0;for (int i = 0; i < n; i++) {bin[i] = Integer.toBinaryString(arr[i]);mx = Math.max(mx, bin[i].length());}for (int i = 0; i < n; i++) {bin[i] = String.join("", Collections.nCopies(mx - bin[i].length(), "0")) + bin[i];}
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