英文:
Problem of printing ABC... and a number in Java
问题
这是我设置的函数：
public int printABCNum(int p) {
char textinfo = 65;
String textValue = "";
while (textinfo < 91) {
textValue += textinfo;
textinfo++;
}
System.out.println(textValue + Integer.toString(p));
}
Eclipse（一个文本编辑器）表示public int printABCNum(p)这部分有问题。基本上我尝试的是运行一个打印"ABCDEFGHIJKLMNOPQRSTUVWXYZ"和一个整数的函数。我对Java还不太熟悉，对于使用它进行编程和查找错误不够有把握，所以请帮忙检查一下！
英文:
This is the function I set:
public int printABCNum(p) {
char textinfo = 65;
String textValue = "";
while (textinfo < 91) {
textValue+=textinfo;
textinfo++;
}
System.out.println(textValue + Integer.toString(p));
Eclipse (a text editor) says that there is a problem with public int printABCNum(p) bit. Basically I'm trying to do is run a function printing "ABCDEFGHIJKLMNOPQRSTUVWXYZ" and an integer. I'm new to Java and is not good 'enough' at programming with it and finding bugs, so please help!
答案1
得分: 2
一个 printABCNum 函数的 p 参数缺少类型说明。根据上下文，它应该是一个 int 类型。另一个问题是你的函数返回类型被定义为 int，但是你并没有返回任何值。
你的代码应该是：
public void printABCNum(int p) {
char textinfo = 65;
String textValue = "";
while (textinfo < 91) {
textValue += textinfo;
textinfo++;
}
System.out.println(textValue + p);
}
英文:
A p parameter of your printABCNum function is missing a type. Based on context it should be an int. Another problem is your function return type is defined to int, but you haven't returned any value.
Your code should be:
public void printABCNum(int p) {
char textinfo = 65;
String textValue = "";
while (textinfo < 91) {
textValue += textinfo;
textinfo++;
}
System.out.println(textValue + p);
}
答案2
得分: 1
看起来有一些问题。
- 如果你不打算返回任何东西，就不应该有返回类型
int。 - 参数需要有类型，像这样：
int p
除此之外看起来还不错。在下面看一下对我有用的完整答案。
public void printABCNum(int p) {
char textinfo = 65;
String textValue = "";
while (textinfo < 91) {
textValue += textinfo;
textinfo++;
}
System.out.println(textValue + Integer.toString(p));
}
英文:
It looks like there's a few things wrong here.
- You shouldn't have a return type
intif you are not returning anything. - The parameter needs to have a type, as such:
int p
Other than that looks fine. Take a look below at full answer that worked for me.
public void printABCNum(int p) {
char textinfo = 65;
String textValue = "";
while (textinfo < 91) {
textValue+=textinfo;
textinfo++;
}
System.out.println(textValue + Integer.toString(p));
}
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