在Java中转置矩阵时遇到错误。

huangapple
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英文:

Transposing a matrix in Java but encountering errors

问题

以下是翻译好的代码部分：

  1. import java.util.*;
  3. public class Transpose {
  4.     private void run() {
  5.         Scanner scan = new Scanner(System.in);
  6.         int Row = scan.nextInt();
  7.         int Col = scan.nextInt();
  8.         char[][] arr = new char[Row][Col];
  9.         for (int i = 0; i < Row; i++) {
  10.             for (int j = 0; j < Col; j++) {
  11.                 arr[i][j] = scan.next().charAt(0);
  12.             }
  13.         }
  14.         for (int j = 0; j < Col; j++) {
  15.             for (int i = 0; i < Row; i++) {
  16.                 System.out.print(arr[i][j]);
  17.             }
  18.             System.out.println();
  19.         }
  20.     }
  22.     public static void main(String[] args) {
  23.         Transpose newTranspose = new Transpose();
  24.         newTranspose.run();
  25.     }
  26. }

请注意，由于您要求只返回翻译后的代码部分，我已经将注释和非代码内容省略。如果您对翻译的代码有任何问题或需要进一步解释，请随时提问。

英文:

I have to ensure that I read in a text file(input) and transpose the matrix whereby the rows become columns.

Sample input:

  1. 2 4
  2. abcd/
  3. efgh

(whereby 2 indicates row and 4 indicates column and / indicates new line)
and output should look like:

  1. ae/
  2. bf/
  3. cg/
  4. dh

This is my code:

  1. import java.util.*;
  3. public class Transpose {
  4. 	private void run() {
  5. 		Scanner scan=new Scanner(System.in);
  6.         int Row= scan.nextInt();
  7.         int Col=scan.nextInt();
  8.         char[][] arr=new char[Row][Col];
  9.         for(int i=0;i&lt;Row;i++){
  10.             for(int j=0;j&lt;Col;j++){
  11.                 arr[i][j]=scan.next().charAt(0);
  12.             }
  13.         }
  14.         for(int j=0;j&lt;Col;j++){
  15.             for(int i=0;i&lt;Row;i++){
  16.                 System.out.print(arr[i][j]);
  17.             }
  18.             System.out.println();
  19.         }
  20. 	}
  22. 	public static void main(String[] args) {
  23. 		Transpose newTranspose = new Transpose();
  24. 		newTranspose.run();
  25. 	}
  26. }

However, I am getting the error:
programme crashed/producing non-zero exit code
Is this a runtime error and how can I go about fixing this.

答案1

得分: 0

  1. 这应该可以工作
  3.     public class Transpose {
  4.         private void run() {
  5.             Scanner scan = new Scanner(System.in);
  6.             System.out.println("行数");
  7.             int 行数 = scan.nextInt();
  8.             System.out.println("列数");
  9.             int 列数 = scan.nextInt();
  10.             char[][] arr = new char[行数][列数];
  11.             for (int i = 0; i < 行数; i++) {
  12.                 for (int j = 0; j < 列数; j++) {
  13.                     System.out.println("输入字符");
  14.                     arr[i][j] = scan.next().charAt(0);
  15.                 }
  16.             }
  17.             for (int j = 0; j < 列数; j++) {
  18.                 for (int i = 0; i < 行数; i++) {
  19.                     System.out.print(arr[i][j] + " ");
  20.                 }
  21.                 System.out.println();
  22.             }
  23.         }
  25.         public static void main(String[] args) {
  26.             Transpose newTranspose = new Transpose();
  27.             newTranspose.run();
  28.         }
  29.     }
  31. 带有期望输出
英文:

This should work

  1. public class Transpose {
  2.     private void run() {
  3.         Scanner scan = new Scanner(System.in);
  4.         System.out.println(&quot;Row&quot;);
  5.         int Row = scan.nextInt();
  6.         System.out.println(&quot;Col&quot;);
  7.         int Col = scan.nextInt();
  8.         char[][] arr = new char[Row][Col];
  9.         for (int i = 0; i &lt; Row; i++) {
  10.             for (int j = 0; j &lt; Col; j++) {
  11.                 System.out.println(&quot;Enter character&quot;);
  12.                 arr[i][j] = scan.next().charAt(0);
  13.             }
  14.         }
  15.         for (int j = 0; j &lt; Col; j++) {
  16.             for (int i = 0; i &lt; Row; i++) {
  17.                 System.out.println(arr[i][j] + &quot; &quot;);
  18.             }
  19.             System.out.println();
  20.         }
  21.     }
  23.     public static void main(String[] args) {
  24.         Transpose newTranspose = new Transpose();
  25.         newTranspose.run();
  26.     }
  27. }

With desired output

答案2

得分: 0

试试这个。

  1. Scanner scan = new Scanner(System.in);
  2. int Row = scan.nextInt();
  3. int Col = scan.nextInt();
  4. scan.nextLine();    // 跳过换行符。
  5. char[][] arr = new char[Row][Col];
  6. for (int i = 0; i < Row; i++) {
  7.     String line = scan.nextLine();
  8.     for (int j = 0; j < Col; j++) {
  9.         arr[i][j] = line.charAt(j);
  10.     }
  11. }
  12. for (int j = 0; j < Col; j++) {
  13.     for (int i = 0; i < Row; i++) {
  14.         System.out.print(arr[i][j]);
  15.     }
  16.     System.out.println();
  17. }

输入：

  1. 2 4
  2. abcd
  3. efgh

输出：

  1. ae
  2. bf
  3. cg
  4. dh
英文:

Try this.

  1. Scanner scan = new Scanner(System.in);
  2. int Row = scan.nextInt();
  3. int Col = scan.nextInt();
  4. scan.nextLine();    // skip newline.
  5. char[][] arr = new char[Row][Col];
  6. for (int i = 0; i &lt; Row; i++) {
  7.     String line = scan.nextLine();
  8.     for (int j = 0; j &lt; Col; j++) {
  9.         arr[i][j] = line.charAt(j);
  10.     }
  11. }
  12. for (int j = 0; j &lt; Col; j++) {
  13.     for (int i = 0; i &lt; Row; i++) {
  14.         System.out.print(arr[i][j]);
  15.     }
  16.     System.out.println();
  17. }

input:

  1. 2 4
  2. abcd
  3. efgh

output:

  1. ae
  2. bf
  3. cg
  4. dh

huangapple
  • 本文由 发表于 2020年8月22日 04:50:24
  • 转载请务必保留本文链接：https://go.coder-hub.com/63529903.html
  • java
  • matrix
  • transpose
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