排序ArrayList内部的ArrayList。

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英文:

Sort ArrayList inside ArrayList

问题

以下是您要翻译的代码部分:

public static void main(String[] args) {

    List<Employee> employees = Arrays.asList(
            new Employee(101, "Ehsan", Arrays.asList("Java", "Spring Boot", "Hibernate", "Spring", "Java", "Net")),
            new Employee(102, "Jamshid", Arrays.asList("Java", "Marketing")),
            new Employee(103, "KK",
                    Arrays.asList("Payroll Management", "Human Resource", "Leaves", "Time Sheet")),
            new Employee(104, "Priya", Arrays.asList("Medicine", "Surgery")));


   for(Employee l: employees) {
       System.out.println(l);
   }


}

期望的输出:
Ehsan : {[Java, Spring Boot, Hibernate, Spring, Java, Net]}
KK : {[Payroll Management, Human Resource, Leaves, Time Sheet]}
Jamshid : {[Java, Marketing]}
Priya : {[Medicine, Surgery]}

英文:

How I can sort skills which is inside another ArrayList as descending order? We have an
Employee class with id, name and
skills. Skills is a separate list.

public static void main(String[] args) {

    List&lt;Employee&gt; employees = Arrays.asList(
            new Employee(101, &quot;Ehsan&quot;, Arrays.asList(&quot;Java&quot;, &quot;Spring Boot&quot;, &quot;Hibernate&quot;, &quot;Spring&quot;, &quot;Java&quot;, &quot;Net&quot;)),
            new Employee(102, &quot;Jamshid&quot;, Arrays.asList(&quot;Java&quot;, &quot;Marketing&quot;)),
            new Employee(103, &quot;KK&quot;,
                    Arrays.asList(&quot;Payroll Management&quot;, &quot;Human Resource&quot;, &quot;Leaves&quot;, &quot;Time Sheet&quot;)),
            new Employee(104, &quot;Priya&quot;, Arrays.asList(&quot;Medicine&quot;, &quot;Surgery&quot;)));


    
  
    
   for(Employee l: employees) {
	   System.out.println(l);
   }

    
}

Expected o/p:
Ehsan : {[Java, Spring Boot, Hibernate, Spring, Java, Net]} 
KK : {[Payroll Management, Human Resource, Leaves, Time Sheet]} 
Jamshid : {[Java, Marketing]} 
Priya : {[Medicine, Surgery]}

答案1

得分: 1

你可以使用 Comparator.comparingInt 来根据技能 List 的大小进行排序。
employees.sort(Comparator.<Employee>comparingInt(e -> e.getSkills().size()).reversed());

在Java 8之前,你可以使用以下方式:

    @Override
    public int compare(final Employee o1, final Employee o2) {
       return Integer.compare(o2.getSkills().size(), o1.getSkills().size());
    }
});```

<details>
<summary>英文:</summary>

You can use `Comparator.comparingInt` to sort based on the sizes of the skills `List`.

employees.sort(Comparator.<Employee>comparingInt(e -> e.getSkills().size()).reversed());


Before Java 8, you can use the following:

employees.sort(new Comparator<Employee>() {
@Override
public int compare(final Employee o1, final Employee o2) {
return Integer.compare(o2.getSkills().size(), o1.getSkills().size());
}
});


</details>



huangapple
  • 本文由 发表于 2020年8月14日 06:15:09
  • 转载请务必保留本文链接:https://go.coder-hub.com/63403930.html
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