SparkJava – 区分大小写的端点

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英文:

SparkJava - Case sensitive endpoints

问题

我有一段使用 SparkJavahttp://sparkjava.com/)的 Java 代码,用于提供 HTTP 端点。

端点的生成方式如下

     get("/xxx/yyy", (request, response) -> {
            ...
            return SOMETHING_TO_RETURN;
     });

采用这种方式我遇到了一个问题
假设我定义了一个端点:'/api/status/car',
但是用户有时会调用 '/api/status/**CAR**'。问题出在这种情况下 URL 的大小写敏感性上

现在我必须解决这个问题**使其不区分大小写**
我已经查看了过滤器例如 'before'),但我不能修改请求的 URL转换为小写),我相信

所以主要问题是使用这种方法定义端点后我如何修改请求的 URL 为小写或者告诉 SparkJava 以不区分大小写的模式映射 URL
英文:

I have a java code which serves http endpoints using SparkJava (http://sparkjava.com/).

Endpoints are generated like that:

 get("/xxx/yyy", (request, response) -> {
        ...
        return SOMETHING_TO_RETURN
 });

With that approach I have a problem:
let's say I have an endpoint defined: '/api/status/car' ,
but users sometimes invoke '/api/status/CAR' instead. So the problem is with case sensitive of url defined like that.

Now I have to fix it somehow: make that case insensitive.
I had take a look on filters (e.g. 'before'), but I can't modify request url (toLowerCase) I believe.

So the main question is: With defining endpoints using that approach, how can I modify request url to be lowercase, or to say sparkjava that urls should be mapped with case insensitive mode.

答案1

得分: 1

URL(除了域名部分)可能始终区分大小写。服务器有权决定,因此用户永远无法知道。您可以在W3.org上了解更多相关信息。

解决您的问题的一种方法是使用请求参数

get("/api/status/:carParam", (request, response) -> {
  if (request.params(":carParam").equalsIgnoreCase("car")) {
    return SOMETHING_TO_RETURN;
  }
});

如果您在/api/status/下有更多的路由,除了car之外,那么您应该将 :carParam 重命名为更通用的名称,例如 :param,然后在处理程序主体内,您将检查此查询参数并根据需要返回正确的返回值。例如:

get("/api/status/:param", (request, response) -> {
  if (request.params(":param").equalsIgnoreCase("car")) {
    return SOMETHING_TO_RETURN_CAR;
  } else if (request.params(":param").equalsIgnoreCase("passenger")) {
    return SOMETHING_TO_RETURN_PASSENGER;
  }
});
英文:

URLs (except the domain name part) might always be case-sensitive. It's up to the server to decide and therefore the user can never know. You can read about it more in W3.org.

One approach to solve your problem could be using request params:

get("/api/status/:carParam", (request, response) -> {
  if (request.params(":carParam").equalsIgnoreCase("car")) {
    return SOMETHING_TO_RETURN;
  }
});

If you have more routes under /api/status/ except car then you should rename :carParam to a more generic name like :param and then inside the handler body, you'd check this query param and return the right return value accordingly. For example:

get("/api/status/:param", (request, response) -> {
  if (request.params(":param").equalsIgnoreCase("car")) {
    return SOMETHING_TO_RETURN_CAR;
  } else if (request.params(":param").equalsIgnoreCase("passenger")) {
    return SOMETHING_TO_RETURN_PASSENGER;
  }
});

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  • 本文由 发表于 2020年4月9日 21:08:19
  • 转载请务必保留本文链接:https://go.coder-hub.com/61121913.html
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