Antlr4/Java : how to make a semantic predicate that skips a token (lexer) according to the parser rule that calls it

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英文:

Antlr4/Java : how to make a semantic predicate that skips a token (lexer) according to the parser rule that calls it

问题

我想要使用我的词法规则
```antlr4
NEW_LINE : '\n' -> skip;

像普通规则一样。理解这一点:我希望忽略换行符,除非它们是必需的,以创建类似Python的语法。例如,在这里,换行符被忽略:

cook("banana",
     "potatoe)

但是在新语句中不可能跳过换行符,就像这样:

cook("banana", "potatoe") varA = 12.4

cook()和赋值之间必须有一个换行符。这就是为什么有时我必须跳过换行符,但仍然需要在其他地方强制它们的原因。

这就是我想到的:

start
	: line*
	;

line
	: line_expression (NEW_LINE | EOF)
	;

line_expression
	: expression
	| assignment
	;

expression
	: Decimal
	| Integer
	| Text
	| Boolean
	;

并创建一个语义谓词,如“如果调用解析器规则不是line,则skip();它。”
现在我只需要帮助来实现这一点。

我希望我表达清楚!

PS:如果不清楚,我正在使用Java作为主要语言。

英文:

I would like to use my lexer rule

NEW_LINE : '\n' -> skip;

Like a normal rule. Understanding by this: I want to ignore the new lines except when they are mandatory, to create a Python similar syntax. For example, here, new lines are ignored:

cook("banana",
     "potatoe)

but it is impossible to skip the new line for a new statement, like this:

cook("banana", "potatoe") varA = 12.4

, there must be a new line between cook() and the assignment. This is why I sometimes have to skip the new lines, but still force them somewhere else.

This is why I got this idea:

start
	: line*
	;

line
	: line_expression (NEW_LINE | EOF)
	;

line_expression
	: expression
	| assignment
	;

expression
	: Decimal
	| Integer
	| Text
	| Boolean
	;

And make a semantic predicate like "if the calling parser rule is not line, skip(); it."
Now I just need help to do that.

I hope I was clear !

PS: I'm using Java as main language if that wasn't clear

答案1

得分: 1

您可以跟踪遇到的(的数量(如果遇到)则减少此数量)。然后,只有在此数量等于零时才创建NL令牌。

这里是一个快速演示:

语法规则 T;

@lexer::members {
  int parensLevel = 0;
}

解析
 : .*? EOF
 ;

OPAR    : '(' {parensLevel++;};
CPAR    : ')' {parensLevel--;};
NUMBER  : [0-9]+ ('.' [0-9]+)?;
STRING  : '"' ~'"'* '"';
ASSIGN  : '=';
COMMA   : ',';
ID      : [a-zA-Z]+;
SPACES  : [ \t]+ -> skip;
NL      : {parensLevel == 0}? [\r\n]+;
NL_SKIP : [\r\n]+ -> skip;

如果您向词法分析器提供以下输入:

cook("banana",
     "potatoe")
  varA = 12.4

将创建以下标记:

ID                        `cook`
'('                       `(` 
STRING                    `"banana"`
','                       `,`
STRING                    `"potatoe"`
')'                       `)`
NL                        `\n`
ID                        `varA`
'='                       `=`
NUMBER                    `12.4`

正如您所看到的,括号内的NL被跳过,而在)之后的NL未被跳过。

英文:

You could keep track of the number of ( you encounter (and decrease this numbers if you encounter a )). Then you only create NL tokens if this number is equal to zero.

Here's a quick demo:

grammar T;

@lexer::members {
  int parensLevel = 0;
}

parse
 : .*? EOF
 ;

OPAR    : '(' {parensLevel++;};
CPAR    : ')' {parensLevel--;};
NUMBER  : [0-9]+ ( '.' [0-9]+)?;
STRING  : '"' ~'"'* '"';
ASSIGN  : '=';
COMMA   : ',';
ID      : [a-zA-Z]+;
SPACES  : [ \t]+ -> skip;
NL      : {parensLevel == 0}? [\r\n]+;
NL_SKIP : [\r\n]+ -> skip;

If you feed the lexer the following input:

cook("banana",
     "potatoe")
  varA = 12.4

the following tokens will be created:

ID                        `cook`
'('                       `(`
STRING                    `"banana"`
','                       `,`
STRING                    `"potatoe"`
')'                       `)`
NL                        `\n`
ID                        `varA`
'='                       `=`
NUMBER                    `12.4`

As you can see, the NL inside the parens is skipped, while the one after the ) is not.

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  • 本文由 发表于 2020年8月14日 01:48:04
  • 转载请务必保留本文链接:https://go.coder-hub.com/63400627.html
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