如何在Python中将存储在列表中的字典中的值从字符串更新为整数?

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英文:

How can I update values in a dictionary that is stored by a list, from strings to integers in Python?

问题

You can change the values inside the dictionary from strings to integers using a nested loop. Here's the corrected code:

for i in ct_dict:
  ct_dict[i] = [int(j) for j in ct_dict[i]]

This code will convert all the values in the dictionary to integers without causing the "dictionary changed size during iteration" error.

英文:
ct_dict = {
    'fr': ['55410', '94560', '52533', '63040', '52533'],
    'de': ['73546', '64090', '60938', '75648', '60938']}

How can i change the values inside the dictionary from string to integer? For example: ['55410', '94560', '52533', '63040', '52533'] to [55410, 94560, 52533, 63040, 52533]

I tried using 2 for loops with update method but got this error:

RuntimeError: dictionary changed size during iteration

Code that got the error:

for i in ct_dict:
  for j in ct_dict[i]:
    ct_dict.update({j:int(j)})

答案1

得分: 1

ct_dict的键是i,而不是j,因此在.update()方法中不应该使用j

但是,如果你只是更新一个键,可以直接将值赋给该键,而不必使用.update()

你需要将int()映射到列表的所有元素上。

for i, vals in ct_dict.items():
    ct_dict[i] = list(map(int, vals))
英文:

The keys of ct_dict are i, not j, so you shouldn't use j in the .update() method.

But if you're just updating one key, just assign to that key rather than using .update().

You need to map int() over all the elements of the list.

for i, vals in ct_dict.items():
    ct_dict[i] = list(map(int, vals))

答案2

得分: 1

你实际上不需要更新字典,只需直接更改列表中的值:

for nums in ct_dict.values():
    nums[:] = map(int, nums)
英文:

You don't actually need to update the dictionary, just change the values in the lists directly:

for nums in ct_dict.values(): 
    nums[:] = map(int,nums)

答案3

得分: 0

您遇到错误是因为您正在尝试在for循环中修改您正在用作引用的字典,而在执行循环时,您不能这样做。

解决方法

假设:

ct_dict = {
    "fr": ["55410", "94560", "52533", "63040", "52533"],
    "de": ["73546", "64090", "60938", "75648", "60938"],
}

最佳选项是使用字典推导式:

new_ct_dict = {key: [int(i) for i in values] for key, values in ct_dict.items()}

但您也可以这样做:

new_ct_dict = {}
for key, values in ct_dict.items():
    new_ct_dict.update({key: []})
    for i in values:
        new_ct_dict[key].append(int(i))

结果:

{'fr': [55410, 94560, 52533, 63040, 52533], 'de': [73546, 64090, 60938, 75648, 60938]}
英文:

You're getting an error because you're trying to modify the dict you're using as a reference in the for loop, while the loop is executing, and you can't do that.

Solution

Assuming:

ct_dict = {
        "fr": ["55410", "94560", "52533", "63040", "52533"],
        "de": ["73546", "64090", "60938", "75648", "60938"],
    }

Best option is use to dict comprehension:

new_ct_dict = {key: [int(i) for i in values] for key, values in ct_dict.items()}

But you can also do:

new_ct_dict = {}
for key, values in ct_dict.items():
    new_ct_dict.update({key: []})
    for i in values:
        new_ct_dict[key].append(int(i))

Result:

{'fr': [55410, 94560, 52533, 63040, 52533], 'de': [73546, 64090, 60938, 75648, 60938]}

答案4

得分: 0

使用 for 循环和列表推导:

my_dict = {'fr': [55410, 94560, 52533, 63040, 52533], 'de': [73546, 64090, 60938, 75648, 60938]}
new_dict = {}

for key, val in my_dict.items():
    new_dict[key] = [int(item) for item in val]

print(new_dict)  # {'fr': [55410, 94560, 52533, 63040, 52533], 'de': [73546, 64090, 60938, 75648, 60938]}

或者,如果你不想创建另一个 dict

my_dict = {'fr': [55410, 94560, 52533, 63040, 52533], 'de': [73546, 64090, 60938, 75648, 60938]}

for key, val in my_dict.items():
    my_dict[key] = [int(item) for item in val]

print(my_dict)  # {'fr': [55410, 94560, 52533, 63040, 52533], 'de': [73546, 64090, 60938, 75648, 60938]}
英文:

Use a for loop and a list comprehension:

my_dict = {'fr': ['55410', '94560', '52533', '63040', '52533'], 'de': ['73546', '64090', '60938', '75648', '60938']}
new_dict = {}

for key, val in my_dict.items():
    new_dict[key] = [int(item) for item in val]

print(new_dict)  # {'fr': [55410, 94560, 52533, 63040, 52533], 'de': [73546, 64090, 60938, 75648, 60938]}

Or, if you'd rather not create another dict:

my_dict = {'fr': ['55410', '94560', '52533', '63040', '52533'], 'de': ['73546', '64090', '60938', '75648', '60938']}

for key, val in my_dict.items():
    my_dict[key] = [int(item) for item in val]

print(my_dict)  # {'fr': [55410, 94560, 52533, 63040, 52533], 'de': [73546, 64090, 60938, 75648, 60938]}

For more on list comprehensions see: https://www.w3schools.com/python/python_lists_comprehension.asp

For more on the dict.items() method see: https://www.w3schools.com/python/ref_dictionary_items.asp

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  • 本文由 发表于 2023年6月1日 04:56:18
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