英文:
I programmatically determine operating system in Java?
问题
我学到的系统特性如下：
System.getProperty("os.arch")
64位计算机的输出：amd64
但当我在64位计算机上使用32位Java版本时，结果是：x86
即使我在64位计算机上安装了32位Java，我该如何获取正确的结果？
谢谢
英文:
I learn the system features as follows:
System.getProperty("os.arch")
Output for 64 bit computer: amd64
but when I use a 32 bit java version on a 64 bit computer, the result is: x86
How can I learn the correct result even though I have java 32 bit java installed on a 64 bit computer?
Thank you
答案1
得分: 2
这个主题在Oracle的Java教程中有详细介绍。
- "os.arch" 操作系统架构
- "os.name" 操作系统名称
- "os.version" 操作系统版本
关于os.arch的值在维基百科上有解释。
（顺便说一句，还存在其他架构，比如ARM。）
第一种情况表示Java在32位机器上运行，或者Java在64位机器上以32位兼容模式运行。
第二种情况表示Java在64位机器上以64位模式运行。
> 即使我在64位计算机上安装了32位Java，我如何知道正确的结果？
（A）我不知道。 （B）你的问题无关紧要。 32位JVM在64位机器上运行时具有32位机器的限制。 从Java的角度来看，主机硬件和操作系统可能是64位的事实是无关紧要的。
英文:
This topic is covered by the Java Tutorials from Oracle.
- "os.arch" Operating system architecture
- "os.name" Operating system name
- "os.version" Operating system version
The values for os.arch are explained on Wikipedia.
x86signifies the 32-bit architecture originally from Intel.amd64signifies the 64-bit extension of that architecture, invented by AMD, later adopted by Intel as well.
(By the way, other architectures exist, such as ARM.)
The first means Java is running on a 32-bit machine, or Java is running on a 64-bit machine in 32-bit compatibility mode.
The second means Java is running in 64-bit mode on a 64-bit machine.
> How can I learn the correct result even though I have java 32 bit java installed on a 64 bit computer?
(A) I don’t know. (B) Your Question is moot. The 32-bit version of the JVM running on a 64-bit machine has the constraints of a 32-bit machine. The JVM only sees what appears to be a 32-bit machine. From the perspective of Java, the fact that the host hardware and OS may be 64-bit is irrelevant.
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