英文:
bad operand types for binary operator '-' in Prioritiy Queue
问题
如何去掉这个消息？
bad operand types for binary operator '-'
Queue<Long> heap = new PriorityQueue( (a,b)->b - a );
first type: Object
second type: Object
import java.util.*;
class solve {
static long minCost(long arr[], int n) {
Queue<Long> heap = new PriorityQueue( (a,b)-> b - a );
long ans = 0;
for( long i : arr )
heap.add(i);
while(!heap.isEmpty()){
long f = heap.poll();
if( heap.isEmpty()) return f+ans;
long s = heap.poll();
ans += f+s;
heap.add(f+s);
}
return ans;
}
public static void main(String[] args) {
long a[] = {4, 3, 2, 6};
System.out.println(minCost(a, 4));
}
}
英文:
How do I get rid off this message?
bad operand types for binary operator '-'
Queue<Long> heap = new PriorityQueue( (a,b)->b - a );
first type: Object
second type: Object
import java.util.*;
class solve {
static long minCost(long arr[], int n) {
Queue<Long> heap = new PriorityQueue( (a,b)-> b - a );
long ans = 0;
for( long i : arr )
heap.add(i);
while(!heap.isEmpty()){
long f = heap.poll();
if( heap.isEmpty()) return f+ans;
long s = heap.poll();
ans += f+s;
heap.add(f+s);
}
return ans;
}
public static void main(String[] args) {
long a[] = {4, 3, 2, 6};
System.out.println(minCost(a, 4));
}
}
答案1
得分: 0
使用非原始的PriorityQueue，并将减法的结果转换为int：
Queue<Long> heap = new PriorityQueue<>((a, b) -> (int) (b - a));
当然，如果长整型之间的差值超过了int的范围，这将导致意外的结果。
更简单的方法是直接使用：
Queue<Long> heap = new PriorityQueue<>(Comparator.reverseOrder());
英文:
Use non-raw PriorityQueue, and cast the result of the subtraction to int:
Queue<Long> heap = new PriorityQueue<>( (a,b)-> (int) (b - a) );
Of course, this will give unexpected results if the difference in the longs exceeds the range of int.
It is easier just to use:
Queue<Long> heap = new PriorityQueue<>(Comparator.reverseOrder());
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