What is the correct way to use multiple charAt's in a if else statement?

trying to check the user's input for the first and last two letters being a Letter datatype for a text-based game. I keep receiving a not a statement error. Not sure why any help would be appreciated.

import java.util.Scanner.*;

public class name info{

  public static void main(String[]args) {
    Scanner console= new Scanner(System.in);
    System.out.println("Enter Job Name:");
    String JobName = console.nextInt();

    if (isLetter(str.charAt(str.length-1))&&(isLetter(str.CharAt(1)){
      system.out.println ("Job name approved");
    }
    else {
     System.out.Println(JobName+" is not a valid job name.");
    }
    System.out.Println("part 1 End");
  }
}

error: ')' expected
error:not a statement

There are two problem in your code. First of all, you have to put an "if" before the line:

(isLetter(str.charAt(str.length-1))&&(isLetter(str.CharAt(1))

So the code is:

import java.util.Scanner.*;

public class EmploymentInfo{

  public static void main(String[]args) {
    Scanner console= new Scanner(System.in);
    System.out.println("Please enter your last name:");
    String LastName = console.nextInt();

    if(LastName.indexOf(" ")<2){ //cond1
      if (isLetter(str.charAt(str.length-1))&&(isLetter(str.CharAt(1)){ //cond2
        //What to do if condition 1 & 2 are verified
      }else{
        //What to do if only cond 1 is verified
      }//end if cond2
    }else {
        //what if cond 1 is NOT verified
    }//end if cond1
    //other code
  }
}

Another problem is the use of indexOf. You want to check if the user input not uses more than two spaces, but indexOf Returns the index within this string of the first occurrence of the specified character (see Oracle site)

As suggested, here a method to find the number of spaces in your string:

public static int foundedSpaces(String s){
  char space = ' ';
  int count = 0;
  for (int i = 0; i < s.length(); i++) {
      if (s.charAt(i) == space) {
          count++;
      }
  }
  return count;
}

You can can call foundedSpaces(LastName)<2 instead of LastName.indexOf(" ")<2

Another problem is the use of java.util.Scanner.nextInt(): this method scans the next token of the input as an int (see this), but you want a string. Replace it with nextLine().

The logic you are using to check the conditions is incorrect. However, I would strongly advise using a regex option with String#matches here:

String LastName = console.nextInt();
if (lastName.matches("(?i)(?!.* .* .* )[A-Z]{2}")) {
    System.out.println("Last name approved");
else {
    System.out.Println(LastName + " is not a valid last name.");
}