英文:
How to calculate! Construct an algorithm that allows you to enter a 4-digit integer and calculate the sum of the first and last digits
问题
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Ingresa el número: ");
Integer numero = sc.nextInt();
char[] nums = numero.toString().toCharArray();
}
英文:
public static void main(String[] args) {
Scanner sc = new Scanner (System.in);
System.out.println("Ingresa el número: ");
Integer numero = sc.nextInt();
char[] nums = numero.toString().toCharArray();
}
答案1
得分: 1
我认为这就是你所寻找的内容。这个算法会首先检查数字中的位数，如果位数为4，则允许继续处理，否则会提示只允许4位整数。
Scanner sc = new Scanner(System.in);
System.out.println("请输入数字：");
Integer number = sc.nextInt();
if (Math.floor(Math.log10(number)) + 1 != 4) {
System.out.println("只允许输入四位整数");
} else {
int last = number % 10;
int first = number / 1000;
System.out.println(last + first);
}
英文:
I think this is what you are looking for. This algo will first check for the number of digits in the number, if they are 4 then allow to process further else it will say integer of 4 digits is allowed.
Scanner sc = new Scanner (System.in);
System.out.println("Ingresa el número: ");
Integer numero = sc.nextInt();
if(Math.floor(Math.log10(numero)) + 1 != 4 ) {
System.out.println("Integer should be of four digits");
} else {
int last = numero%10;
int first = numero/1000;
System.out.println(last+first);
}
答案2
得分: 1
这是你想要的：
int answer = n％10 + n／1000;
它将数字 n 的第一个和最后一个数字相加。
英文:
I think this is what you want :
int answer = n%10 + n/1000;
It adds the first and last digit of the number n.
答案3
得分: 0
你可以这样做：
Scanner sc = new Scanner(System.in);
System.out.println("请输入数字：");
String number = sc.nextLine();
Integer result = Integer.parseInt(String.valueOf(number.charAt(0))) +
Integer.parseInt(String.valueOf(number.charAt(number.length() - 1)));
英文:
You can do something like this
Scanner sc = new Scanner (System.in);
System.out.println("Ingresa el número: ");
String numero = sc.nextLine();
Integer result = Integer.parseInt(numero.charAt(0)+"") +
Integer.parseInt(number.charAt(numero.length()-1)+"");
答案4
得分: 0
你的意思是像这样吗？
public class Adder {
public static void main(String[] args) {
int num = 2008;
// 寻找最后一位数字
int sum = num % 10;
// 寻找第一位数字
while (num >= 10) {
num /= 10;
}
sum += num;
System.out.println(sum);
}
}
英文:
You mean like this?
public class Adder {
public static void main(String[] args) {
int num=2008;
//Find last number
int sum = num%10;
//Find first number
while (num >= 10){
num /= 10;
}
sum +=num;
System.out.println(sum);
}
}
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