无法正确解析和显示Json

huangapple
go评论112阅读模式
英文:

Cannot properly parse and display Json

问题

  1. while((inputLine = in.readLine()) != null)
  2. {
  3.     jsonData = inputLine;
  4.     System.out.println(jsonData);
  5. }
  7. JSONObject object = null;
  8. try {
  9.     object = (JSONObject) new JSONParser().parse(jsonData);
  10. } catch (ParseException e) {
  11.     // TODO Auto-generated catch block
  12.     e.printStackTrace();
  13. }
  14. JSONObject weather = (JSONObject) object.get("weather");
  15. String description = weather.get("description").toString();
  17. System.out.println(description);
  19. in.close();

以上代码产生了以下错误：
无法正确解析和显示Json

我附上的代码从第38行开始。我想尝试从我解析的Json中打印出“description”字段。

来自json的相关部分如下：

    “weather”：[ { “id”：800, “main”：“晴朗”， “description”：“晴空”， “icon”：“01n” } ]，

英文: 
  1. while((inputLine = in.readLine()) != null)
  2. {
  3. 	jsonData = inputLine;
  4. 	System.out.println(jsonData);
  5. 	
  6. }
  8. JSONObject object = null;
  9. try {
  10. 	object = (JSONObject) new JSONParser().parse(jsonData);
  11. } catch (ParseException e) {
  12. 	// TODO Auto-generated catch block
  13. 	e.printStackTrace();
  14. }
  15. JSONObject weather = (JSONObject) object.get("weather");
  16. String description = weather.get("description").toString();
  18. System.out.println(description);
  19. 		
  20. in.close();

The above code produces the following error:
无法正确解析和显示Json

The code I've attached starts at line 38. I want to try to print out the "description" field from the Json I have parsed.

The relevant part from the json is:

  1. "weather": [ { "id": 800, "main": "Clear", "description": "clear sky", "icon": "01n" } ],

答案1

得分: 1

你正在将一个 JSONArray 解析为 JsonObject，在你的代码中的以下行：

  1. JSONObject weather = (JSONObject) object.get("weather");

weather 是一个 JsonArray
我尝试了以下代码，它对我有效。

  1.     public static void main(String[] args) {
  2.        JSONObject jsonObject = new JSONObject("{\"weather\": [ { \"id\": 800, \"main\": \"Clear\", \"description\": \"clear sky\", \"icon\": \"01n\" } ]}");
  3.        JSONArray weatherArray = jsonObject.getJSONArray("weather");
  4.        JSONObject weatherJson = weatherArray.getJSONObject(0);
  5.        System.out.println(weatherJson.get("description"));
  6.     }

输出

  1. clear sky
英文:

You are Parsing a JSONArray to JsonObject
at below line in ur code

  1. JSONObject weather = (JSONObject) object.get("weather");

weather is a JsonArray
I tried below code it worked for me.

  1.     public static void main(String[] args) {
  2.        JSONObject jsonObject = new JSONObject("{\"weather\": [ { \"id\": 800, \"main\": \"Clear\", \"description\": \"clear sky\", \"icon\": \"01n\" } ]}");
  3.        JSONArray weatherArray = jsonObject.getJSONArray("weather");
  4.        JSONObject weatherJson = weatherArray.getJSONObject(0);
  5.        System.out.println(weatherJson.get("description"));
  6.     }

output

  1. clear sky

huangapple
  • 本文由 发表于 2020年9月30日 14:29:05
  • 转载请务必保留本文链接：https://go.coder-hub.com/64132026.html
  • java
  • json
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