英文:
How to check for a file name?
问题
好的，以下是您要翻译的内容：
好的，我知道标题确实很模糊，但我无法准确表达我的问题，因此我无法通过搜索引擎找到答案；这就是为什么我向大家请教的原因。
基本上，我有一个构造函数，它接受一个文件输入，并根据文件名（在我的示例中，我们使用file.txt或employees.txt）对其进行处理。现在我不知道这是否是一个好主意，或者是否有另一种方法可以创建多个相似的构造函数。以下是我目前的代码，感谢您的帮助！：
public class CarDealershipSystem {
public CarDealershipSystem(File file) {
try (BufferedReader br = new BufferedReader(new FileReader(file))) {
ArrayList<Car> carObjectArray = new ArrayList<Car>();
while((br.readLine()) != null) {
if (file == cars.txt) {
String line = br.readLine();
String[] lineArray = line.split(",");
Car car = new Car();
car.setMake(lineArray[0]);
car.setModel(lineArray[1]);
carObjectArray.add(car);
}
else if (file == employees.txt) {
;
}
}
}catch(IOException e) {
e.getLocalizedMessage();
e.printStackTrace();
}
}
}
英文:
Alright I know the title is really vague but I can't wrap my head around how to word my problem and therefore I can't google it; that's why I'm asking you guys
Basically I have a constructor that takes a file input and depending on the file name (in my example we're using file.txt or employees.txt) we do something to it. Now I have no idea if this is even a good idea or not or if there is another way to do multiple duplicate constructors. Here's my code so far and thanks for helping me out!:
public class CarDealershipSystem {
public CarDealershipSystem(File file) {
try (BufferedReader br = new BufferedReader(new FileReader(file))) {
ArrayList<Car> carObjectArray = new ArrayList<Car>();
while((br.readLine()) != null) {
if (file == cars.txt) {
String line = br.readLine();
String[] lineArray = line.split(",");
Car car = new Car();
car.setMake(lineArray[0]);
car.setModel(lineArray[1]);
carObjectArray.add(car);
}
else if (file == employees.txt) {
;
}
}
}catch(IOException e) {
e.getLocalizedMessage();
e.printStackTrace();
}
}
}
答案1
得分: 3
简单的答案是：
if (file.getName().equals("cars.txt")) {
...
} else if (file.getName().equals("employees.txt")) {
...
}
但这里存在一些更深层次的问题：
-
一个单一的方法或构造函数读取文件，而文件可以具有两种完全不同的格式……和含义，这似乎很奇怪（错误！）。
-
构建一个汽车经销商，只有汽车或只有员工似乎很奇怪（错误！）。汽车经销商需要既有汽车又有员工。
英文:
The simple answer is
if (file.getName().equals("cars.txt")) {
...
else if (file.getName().equals("employees.txt")) {
...
}
But there are some deeper problems here:
-
It seems odd (wrong!) to have a single method or constructor that reads a file that can have two completely different formats ... and meanings.
-
It seems odd (wrong!) that you can construct a car dealership with either only cars, or only employees. A car dealership needs to have both cars and employees
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