创建使用Spring Boot的QR码,并将其转换为Base64字符串。

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英文:

Creating QR Code as Base64 String using Spring Boot

问题

我正在使用 Spring Boot 创建一个微服务,其中涉及文件处理。我的任务是将 QR 码写入图像文件,并对其进行 base64 编码以便在网络上传输。因为我需要先将数据写入图像文件,然后读取并进行 base64 编码,所以我需要首先创建图像文件,然后再将数据写入它。
是创建一个临时文件夹并在其中保存文件?还是在根目录下创建一个文件夹并保存文件?抑或是使用 java.io.tmpdir ....
注意:一旦我编码后,就不再需要这个文件。而且有很多用户将通过 REST API 使用此服务。
我想知道最佳做法是什么。

英文:

I am creating a microservice using spring boot where in i have a file handling.
My task is to write the QR code to image file and base64 encode to transfer over network.
Because I need to write to an image file and then read and then base64 encode it , I need to first create the image file and then write to it.
Creating a temperory folder and keep the file ?, create a folder in root directory and keep the file? or use the java.io.tmpdir ....
Note: I have no use of this file once I encode it. Also there are lot of user to whom we will be exposing this service as rest api.
I want to know what is the best way to do this.

答案1

得分: 2

如果您正在使用 https://github.com/zxing/zxing 库,即

    <dependency>
      <groupId>com.google.zxing</groupId>
      <artifactId>javase</artifactId>
      <version>3.2.1</version>
    </dependency>

那么类似以下的代码将会有效。

@RestController
public class TestController {

    @GetMapping(value = "/test")
    public QrInfo getQrInfo() throws Exception {

        String url = "https://news.bbc.co.uk";

        int imageSize = 200;
        BitMatrix matrix = new MultiFormatWriter().encode(url, BarcodeFormat.QR_CODE,
            imageSize, imageSize);
        ByteArrayOutputStream bos = new ByteArrayOutputStream();
        MatrixToImageWriter.writeToStream(matrix, "png", bos);
        String image = Base64.getEncoder().encodeToString(bos.toByteArray()); // base64 encode

        // return QrInfo
        QrInfo qrInfo = new QrInfo();
        qrInfo.setUrl(url);
        qrInfo.setImage(image);
        return qrInfo;
    }

}

@Data // lombok for brevity
class QrInfo {

    private String url;
    private String image;

}

注意:这个方法不会写入任何文件,而是都在内存中使用 ByteArrayOutputStream 进行操作。

如果您访问这个端点,您将会看到如下内容: -

{
	"url": "https://news.bbc.co.uk",
	"image": "iVBORw0KGgoAAAANSUhEUgAAAMgAAADIAQAAAACFI5MzAAABGUlEQVR42u2YSw7DIAxEzYpjcFM+N+UYrErtMUkjpd2WWQQlyudtLI89JpH5a8lDHvJnUkVXmkMPKcMeAg1peo70inrpRbm/ISFDwkhNX4NUSWxEo26WVFKisgc2ArWncSO3OthJvEs0nTju/bOT+NJKzJK++c5OovJWRIob2AwNsf6YXWJ3eFGbgXS4skgEGafaDGSifVONS/ZCQ/Q2YI5l8BdSS0ImwtTezehjiM9C3FG8fbVdykft/URTeEY918hlIZZFC9Yq0Rw6ns63nyxXtkTCYK6VuJv4NKvmMdgFMBHfBbRjb8JFxgoWW04RPmKfEaY2pgcZcT/OsL3GQ5baFrUN23iZZrvJ6pKjDJFXFvL8P3jIfvIGvNX7jsCaJvEAAAAASUVORK5CYII="
}

如果您将这个 Base64 码粘贴到例如 https://codebeautify.org/base64-to-image-converter 并且用手机摄像头对准,您将会看到这个 URL。

创建使用Spring Boot的QR码,并将其转换为Base64字符串。

如果您想要在渲染时展示这个内容,方法很简单,例如在 React 中(任何 JavaScript 方法类似)。

<img src={`data:image/png;base64,${image}`} />

我喜欢这个方法,因为如果您需要生成双因素认证码(2FA),您可以同时传递随机密钥和 QR 码,这对于备份很有用,以备用户无法访问移动设备的情况。

英文:

If you are using the https://github.com/zxing/zxing library i.e.

    &lt;dependency&gt;
      &lt;groupId&gt;com.google.zxing&lt;/groupId&gt;
      &lt;artifactId&gt;javase&lt;/artifactId&gt;
      &lt;version&gt;3.2.1&lt;/version&gt;
    &lt;/dependency&gt;

Then something like the following will work.

@RestController
public class TestController {

    @GetMapping(value = &quot;/test&quot;)
    public QrInfo getQrInfo() throws Exception {

        String url = &quot;https://news.bbc.co.uk&quot;;

        int imageSize = 200;
        BitMatrix matrix = new MultiFormatWriter().encode(url, BarcodeFormat.QR_CODE,
            imageSize, imageSize);
        ByteArrayOutputStream bos = new ByteArrayOutputStream();
        MatrixToImageWriter.writeToStream(matrix, &quot;png&quot;, bos);
        String image = Base64.getEncoder().encodeToString(bos.toByteArray()); // base64 encode

        // return QrInfo
        QrInfo qrInfo = new QrInfo();
        qrInfo.setUrl(url);
        qrInfo.setImage(image);
        return qrInfo;
    }

}


@Data // lombok for brevity
class QrInfo {

    private String url;
    private String image;

}

> NOTE: This approach doesn't write any files but does it all in-memory using a ByteArrayOutputStream .

If you hit this endpoint you'll see the following: -

{
	&quot;url&quot;: &quot;https://news.bbc.co.uk&quot;,
	&quot;image&quot;: &quot;iVBORw0KGgoAAAANSUhEUgAAAMgAAADIAQAAAACFI5MzAAABGUlEQVR42u2YSw7DIAxEzYpjcFM+N+UYrErtMUkjpd2WWQQlyudtLI89JpH5a8lDHvJnUkVXmkMPKcMeAg1peo70inrpRbm/ISFDwkhNX4NUSWxEo26WVFKisgc2ArWncSO3OthJvEs0nTju/bOT+NJKzJK++c5OovJWRIob2AwNsf6YXWJ3eFGbgXS4skgEGafaDGSifVONS/ZCQ/Q2YI5l8BdSS0ImwtTezehjiM9C3FG8fbVdykft/URTeEY918hlIZZFC9Yq0Rw6ns63nyxXtkTCYK6VuJv4NKvmMdgFMBHfBbRjb8JFxgoWW04RPmKfEaY2pgcZcT/OsL3GQ5baFrUN23iZZrvJ6pKjDJFXFvL8P3jIfvIGvNX7jsCaJvEAAAAASUVORK5CYII=&quot;
}

If you paste the Base64 into e.g https://codebeautify.org/base64-to-image-converter and point camera from your phone you will see the URL.

创建使用Spring Boot的QR码,并将其转换为Base64字符串。

If you rendering this out it is easy i.e. in React (any JavaScript approach will be similar).

&lt;img src={`data:image/png;base64,${image}`} /&gt;

I like this approach as if you are e.g. generate 2FA codes you can pass down both the random secret and the QR code - useful to have both as a backup if the user doesn't have access to a mobile device.

答案2

得分: 0

你可以在你的文件系统中的指定文件夹里轻松地执行此操作,一旦传输完成,你可以删除该文件。但是由于这个操作是通过 REST API 暴露的,所以并发和文件冲突可能是一个问题。为了避免这种情况,你可以为每个文件名赋予唯一的值,这样相同文件名的冲突就可以避免了。

一个方法是使用 UUID 来为文件名命名并将文件存储为该名称在文件系统中。这将确保不会发生冲突。

String fileName = UUID.randomUUID().toString();
英文:

You can do this in a designated folder in your file-system easily and once you are done with the transfer, you can remove the file. But since, this operation is exposed over a rest api, concurrency and file collision can be an issue. To avoid that you can give unique to every file-name, that way same file-name collision can be avoided.

One approach could be to UUID for writing the file-name and storing the file with this name in the file-system. It will ensure collision doesn't occur.

String fileName = UUID.randomUUID().toString();

</details>



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  • 本文由 发表于 2020年4月5日 00:44:33
  • 转载请务必保留本文链接:https://go.coder-hub.com/61031411.html
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