英文:
Parsing File upload in Spring
问题
我想解析接受多部分/form-data文件的请求体。目前，当我尝试将inputStream打印为字符串时，我得到如下内容：
----------------------------559363225496099939024171Content-Disposition: form-data;name="file";filename="upload.txt"Content-Type: text/plain{"documents": [{"id": "1","text": "abc"}]}----------------------------559363225496099939024171
以下是我的controller.java：
@POST@Path("/modelInfo")@Produces({ "application/json" })@Consumes(MediaType.MULTIPART_FORM_DATA)public Response getModel(InputStream file) throws IOException {InputStreamReader isReader = new InputStreamReader(file, StandardCharsets.UTF_8);//Creating a BufferedReader objectBufferedReader reader = new BufferedReader(isReader);StringBuffer sb = new StringBuffer();String str;while ((str = reader.readLine()) != null) {sb.append(str);}return Response.status(Response.Status.OK).entity(sb.toString()).build();}
upload.txt
{"documents": [{"id": "1","text": "abc"}]}
因此，基本上，我将sb.toString()发送回响应体。
我的问题是，如何从上面获取的响应中提取只有内容数据？
我尝试使用MultipartFile，但仍然没有成功。
英文:
I want to parse request body which accepts a file as multipart/form-data. Currently, when I try to print the inputStream as string, I get like below:
----------------------------559363225496099939024171Content-Disposition: form-data;name="file";filename="upload.txt"Content-Type: text/plain{"documents": [{"id": "1","text": "abc"}]}----------------------------559363225496099939024171
Below is my controller.java
@POST@Path("/modelInfo")@Produces({ "application/json" })@Consumes(MediaType.MULTIPART_FORM_DATA)public Response getModel(InputStream file) throws IOException {InputStreamReader isReader = new InputStreamReader(file, StandardCharsets.UTF_8);//Creating a BufferedReader objectBufferedReader reader = new BufferedReader(isReader);StringBuffer sb = new StringBuffer();String str;while ((str = reader.readLine()) != null) {sb.append(str);}return Response.status(Response.Status.OK).entity(sb.toString()).build();}
upload.txt
{"documents": [{"id": "1","text": "abc"}]}
So basically, I am sending sb.toString() back to response body.
My question is, how to extract only the content data from the above response I am getting?
I tried using MultipartFile, still no luck
答案1
得分: 0
@POST
@Path("/modelInfo")
@Produces({ "application/json" })
@Consumes(MediaType.MULTIPART_FORM_DATA)
public Response getModel(@RequestParam("file") MultipartFile file) throws IOException {
InputStreamReader isReader = new InputStreamReader(file.getInputStream(), StandardCharsets.UTF_8);
...
英文:
The rest endpoint method parameter should be of type MultipartFile then you can get the file input stream from that object
@POST@Path("/modelInfo")@Produces({ "application/json" })@Consumes(MediaType.MULTIPART_FORM_DATA)public Response getModel(@RequestParam("file") MultipartFile file) throws IOException {InputStreamReader isReader = new InputStreamReader(file.getInputStream(), StandardCharsets.UTF_8);...
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