抑制单行多命令的Makefile规则的输出。

huangapple go评论55阅读模式
英文:

surpress output of single line, multi command Makefile recipe

问题

我想抑制Makefile中某些命令的输出

例如,我有一个目标,stagel

stagel:
    cd scripts && npm list body-parser || npm install body-parser
    node scripts/app.js

我想抑制目标中第一行的输出。

我尝试过 @cd scripts && npm list body-parser || npm install body-parser,但仍然会得到输出。我还尝试了在每个npm命令后添加@,但得到了@npm: command not found

英文:

I would like to surpress the output of certain commands in my Makefile

For instance I have a target, stagel

stagel:
	cd scripts && npm list body-parser || npm install body-parser
    node scripts/app.js

I'd like to surpress the output of first line in the target.

I tried, @cd scripts && npm list body-parser || npm install body-parser, but I still got the output. I also tried appending @ to each npm command, but got, @npm: command not found

答案1

得分: 1

我认为这个命令是不正确的:

cd scripts && npm list body-parser || npm install body-parser

这句话的意思是:“运行cd scripts:如果cd成功,运行npm list body-parser,如果cd失败,运行npm install body-parser”。我不确定您确切想做什么,但我怀疑您想表达的是:“首先cd scripts,然后运行npm list body-parser,如果失败则运行npm install body-parser”。要实现这一点,您需要类似这样的写法:

cd scripts && { npm list body-parser || npm install body-parser; }

关于“抑制第一行的输出”的含义并不清楚。您是指不希望make打印出它正在运行的命令行吗?还是指不想显示命令的输出?

如果是前者,您的尝试@cd ...将会达到这个效果。因为您对此不满意,我只能假设您指的是后者。

Make无法控制您运行的命令所生成的输出。如果您想抑制该输出,您需要自己使用正常的shell重定向操作来实现。例如:

stagel:
        cd scripts && { npm list body-parser || npm install body-parser; } >/dev/null
        node scripts/app.js
英文:

I think this command is not right:

cd scripts && npm list body-parser || npm install body-parser

This says, "run cd scripts: if the cd works, run npm list body-parser and if the cd fails, run npm install body-parser". I don't know what you're trying to do for sure but I suspect what you want to say is, "first cd scripts, then run npm list body-parser and if that fails run npm install body-parser". To do that you'll need something like this:

cd scripts && { npm list body-parser || npm install body-parser; }

It's not clear what you mean by "supporess the output of first line". Do you mean, you don't want make to print out the command line it is running? Or do you mean, you don't want the output from the command to be shown?

If the former then your attempt @cd ... will do that. Since you weren't happy with that I can only assume you mean the latter.

Make does not have anything to say about the output that commands you run generate. If you want to suppress that output you have to do it yourself, using normal shell redirection operations. For example:

stagel:
        cd scripts && { npm list body-parser || npm install body-parser; } >/dev/null
        node scripts/app.js

huangapple
  • 本文由 发表于 2020年1月7日 02:01:14
  • 转载请务必保留本文链接:https://go.coder-hub.com/59616816.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定